Agl202
  • Agl202
Medal For help... -> Solve for x, given the equation Square root of x minus 5+ 7 = 11. x = 21, solution is extraneous x = 21, solution is not extraneous x = 81, solution is extraneous x = 81, solution is not extraneous
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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Agl202
  • Agl202
@ganeshie8 hlp.. plz...
Nnesha
  • Nnesha
\[\huge\rm \sqrt{x-5}+7=11\] like this ?
Nnesha
  • Nnesha
or 7 is also under the root ?

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Agl202
  • Agl202
So it would be x=21 right?
Agl202
  • Agl202
So, A.?
Nnesha
  • Nnesha
what is an extraneous and non-extraneous solution means ?
Agl202
  • Agl202
Extraneous Solution is a solution of the simplified form of an equation that does not satisfy the original equation.
Nnesha
  • Nnesha
okay. substitute x for its value into the original equation if both sides are equal then 21 isn't extraneous solution if both sides aren't equal then 21 is an extraneous solution
Nnesha
  • Nnesha
\[\huge\rm \sqrt{x-5}+7=11\] replace x with 21 solve left side
Agl202
  • Agl202
I don't get it. ^
Nnesha
  • Nnesha
x=21 right now to check if it's an extraneous or non-extraneous you should substitute x for 21
Agl202
  • Agl202
I get a non-extraneous.
Nnesha
  • Nnesha
right \[\sqrt{21-5}+7=11\] both sides are equal so it would be non-ex
Agl202
  • Agl202
You deserve a medal! Thx u so much!!! :D
Nnesha
  • Nnesha
yw!
Agl202
  • Agl202
I got it right!!
Nnesha
  • Nnesha
nice

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