## anonymous one year ago Help with three problems.

1. anonymous

2. anonymous

I got -1, 5, 5

3. anonymous

4. Nnesha

how did you get -1 ?

5. anonymous

6. anonymous

I did the first equation x=/ 5

7. Nnesha

yes right so substitute x for 3

8. anonymous

Omg I see what I did.. 8 is the correct answer

9. Nnesha

yes right

10. anonymous

I miss read my own writing. I thought I wrote x^3 when it was x^2

11. anonymous

Are the other two answers correct?

12. Nnesha

yes

13. anonymous

Okay.. For the other two questions I posted im stuck.

14. anonymous

I got to 10/ (x+h) - 10/x all over h

15. anonymous

lcd= x(x+h) .. My example does something weird so im stuck here

16. Nnesha

how did you get 10 ? can you please show the work so i can find the mistakes :=)

17. anonymous

Oh my gosh. Sorry it some how posted the same question twice and not the correct question 22.. One second

18. anonymous

19. anonymous

That picture above is the question I was talking about.. @Nnesha

20. Nnesha

oh alright wait a sec

21. anonymous

22. Nnesha

$\huge\rm \frac{\color{ReD}{ \frac{ 10 }{ x+h }-\frac{ 10 }{ x}} }{ h }$ first deal with the top red part find the common denominator

23. anonymous

x(x+h)

24. Nnesha

yes right so what about the numerator ?

25. Nnesha

$\huge\rm \frac{\color{ReD}{ \frac{??? }{ x(x+h )} } }{ h }$ multiply the numerator of first by denominator of the 2nd fraction multiply the numerator of 2nd fraction by denominator of first fraction

26. anonymous

Um what? I assumed it would leave me with 10x- 10(x+h) all over h

27. Nnesha

that's the numerator of top fraction $\huge\rm \frac{\color{ReD}{ \frac{10x-10(x+h) }{ x(x+h )} } }{ h }$ like this

28. anonymous

??? How do you still have x(x+h) shouldnt it cancel out?

29. Nnesha

how would you cancel out that ? that's our common denominator

30. anonymous

Thats what happens when you get rid of fractions..

31. Nnesha

alright here is the example $\huge\rm \frac{ a }{ b } +\frac{ b }{ d}$ $\huge\rm \frac{ ad+ cb }{ bd }$i would the common denominator

32. anonymous

Um okay?

33. anonymous

Whats the next step?

34. Nnesha

$\huge\rm \frac{\color{ReD}{ \frac{10x-10(x+h) }{ x(x+h )} } }{ h }$ we should change division to multiplication to do that you should multiply the top with the reciprocal of the bottom

35. anonymous

Bottom as in x(x+h) or h?

36. Nnesha

$\huge\rm \frac{\color{ReD}{ \frac{ a }{ b }} }{ \frac{ c }{ d } }=\color{reD}{\frac{a}{b}} \times \frac{d}{c}$ like this

37. Nnesha

$\huge\rm \frac{\color{ReD}{ \frac{10x-10(x+h) }{ x(x+h )} } }{ \frac{h}{1} }$ h

38. Nnesha

h is same as h over 1

39. anonymous

Multiple by h/1?

40. anonymous

10x-10(x+h)/x(x+h) * h/1

41. Nnesha

what is the reciprocal of h/1 ?

42. anonymous

1/h

43. Nnesha

yes so multiply bye 1/h

44. anonymous

Okay

45. Nnesha

$\huge\rm \color{ReD}{ \frac{10x-10(x+h) }{ x(x+h )} \times \frac{1}{h}}$ now distribute 10(x+h) multiply x(x+h)

46. anonymous

Okay

47. anonymous

-10h/ x^2+x * 1/h

48. anonymous

-10h/ x^2+xh

49. Nnesha

hmm there is a mistake in the denominator

50. Nnesha

$\huge\rm \frac{ -10h }{ x(x+h) \times h }$ distribute x+h by x

51. anonymous

xh^2 +xh^2

52. anonymous

Right or no?

53. Nnesha

yes right h is common factor we take it out $\huge\rm \frac{ -10h }{ h(x^2+xh) }$now simplify

54. anonymous

-10/ x^2+h

55. Nnesha

hmm

56. Nnesha

$\huge\rm \frac{ -10\cancel{h} }{ \cancel{h}(x^2+xh) }$ so final answer would be what ?

57. anonymous

-10/ x^2 +xh .. I noticed I forgot the second x

58. Nnesha

yes right

59. anonymous

Okay.. For the next one with the square root I have nothing.. I wasnt sure where to start

60. anonymous

I can put it in a new question if youd like

61. Nnesha

which one ?

62. anonymous

Ill tag you on it..

63. Nnesha

alright