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Destinyyyy

  • one year ago

Help with three problems.

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  1. Destinyyyy
    • one year ago
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  2. Destinyyyy
    • one year ago
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    I got -1, 5, 5

  3. Destinyyyy
    • one year ago
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  4. Nnesha
    • one year ago
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    how did you get -1 ?

  5. Destinyyyy
    • one year ago
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  6. Destinyyyy
    • one year ago
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    I did the first equation x=/ 5

  7. Nnesha
    • one year ago
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    yes right so substitute x for 3

  8. Destinyyyy
    • one year ago
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    Omg I see what I did.. 8 is the correct answer

  9. Nnesha
    • one year ago
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    yes right

  10. Destinyyyy
    • one year ago
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    I miss read my own writing. I thought I wrote x^3 when it was x^2

  11. Destinyyyy
    • one year ago
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    Are the other two answers correct?

  12. Nnesha
    • one year ago
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    yes

  13. Destinyyyy
    • one year ago
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    Okay.. For the other two questions I posted im stuck.

  14. Destinyyyy
    • one year ago
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    I got to 10/ (x+h) - 10/x all over h

  15. Destinyyyy
    • one year ago
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    lcd= x(x+h) .. My example does something weird so im stuck here

  16. Nnesha
    • one year ago
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    how did you get 10 ? can you please show the work so i can find the mistakes :=)

  17. Destinyyyy
    • one year ago
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    Oh my gosh. Sorry it some how posted the same question twice and not the correct question 22.. One second

  18. Destinyyyy
    • one year ago
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  19. Destinyyyy
    • one year ago
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    That picture above is the question I was talking about.. @Nnesha

  20. Nnesha
    • one year ago
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    oh alright wait a sec

  21. Destinyyyy
    • one year ago
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    Okay. Sorry about that

  22. Nnesha
    • one year ago
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    \[\huge\rm \frac{\color{ReD}{ \frac{ 10 }{ x+h }-\frac{ 10 }{ x}} }{ h }\] first deal with the top red part find the common denominator

  23. Destinyyyy
    • one year ago
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    x(x+h)

  24. Nnesha
    • one year ago
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    yes right so what about the numerator ?

  25. Nnesha
    • one year ago
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    \[\huge\rm \frac{\color{ReD}{ \frac{??? }{ x(x+h )} } }{ h }\] multiply the numerator of first by denominator of the 2nd fraction multiply the numerator of 2nd fraction by denominator of first fraction

  26. Destinyyyy
    • one year ago
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    Um what? I assumed it would leave me with 10x- 10(x+h) all over h

  27. Nnesha
    • one year ago
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    that's the numerator of top fraction \[\huge\rm \frac{\color{ReD}{ \frac{10x-10(x+h) }{ x(x+h )} } }{ h }\] like this

  28. Destinyyyy
    • one year ago
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    ??? How do you still have x(x+h) shouldnt it cancel out?

  29. Nnesha
    • one year ago
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    how would you cancel out that ? that's our common denominator

  30. Destinyyyy
    • one year ago
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    Thats what happens when you get rid of fractions..

  31. Nnesha
    • one year ago
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    alright here is the example \[\huge\rm \frac{ a }{ b } +\frac{ b }{ d}\] \[\huge\rm \frac{ ad+ cb }{ bd }\]i would the common denominator

  32. Destinyyyy
    • one year ago
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    Um okay?

  33. Destinyyyy
    • one year ago
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    Whats the next step?

  34. Nnesha
    • one year ago
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    \[\huge\rm \frac{\color{ReD}{ \frac{10x-10(x+h) }{ x(x+h )} } }{ h }\] we should change division to multiplication to do that you should multiply the top with the `reciprocal` of the bottom

  35. Destinyyyy
    • one year ago
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    Bottom as in x(x+h) or h?

  36. Nnesha
    • one year ago
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    \[\huge\rm \frac{\color{ReD}{ \frac{ a }{ b }} }{ \frac{ c }{ d } }=\color{reD}{\frac{a}{b}} \times \frac{d}{c}\] like this

  37. Nnesha
    • one year ago
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    \[\huge\rm \frac{\color{ReD}{ \frac{10x-10(x+h) }{ x(x+h )} } }{ \frac{h}{1} }\] h

  38. Nnesha
    • one year ago
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    h is same as h over 1

  39. Destinyyyy
    • one year ago
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    Multiple by h/1?

  40. Destinyyyy
    • one year ago
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    10x-10(x+h)/x(x+h) * h/1

  41. Nnesha
    • one year ago
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    what is the reciprocal of h/1 ?

  42. Destinyyyy
    • one year ago
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    1/h

  43. Nnesha
    • one year ago
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    yes so multiply bye 1/h

  44. Destinyyyy
    • one year ago
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    Okay

  45. Nnesha
    • one year ago
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    \[\huge\rm \color{ReD}{ \frac{10x-10(x+h) }{ x(x+h )} \times \frac{1}{h}} \] now distribute 10(x+h) multiply x(x+h)

  46. Destinyyyy
    • one year ago
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    Okay

  47. Destinyyyy
    • one year ago
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    -10h/ x^2+x * 1/h

  48. Destinyyyy
    • one year ago
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    -10h/ x^2+xh

  49. Nnesha
    • one year ago
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    hmm there is a mistake in the denominator

  50. Nnesha
    • one year ago
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    \[\huge\rm \frac{ -10h }{ x(x+h) \times h }\] distribute x+h by x

  51. Destinyyyy
    • one year ago
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    xh^2 +xh^2

  52. Destinyyyy
    • one year ago
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    Right or no?

  53. Nnesha
    • one year ago
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    yes right h is common factor we take it out \[\huge\rm \frac{ -10h }{ h(x^2+xh) }\]now simplify

  54. Destinyyyy
    • one year ago
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    -10/ x^2+h

  55. Nnesha
    • one year ago
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    hmm

  56. Nnesha
    • one year ago
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    \[\huge\rm \frac{ -10\cancel{h} }{ \cancel{h}(x^2+xh) }\] so final answer would be what ?

  57. Destinyyyy
    • one year ago
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    -10/ x^2 +xh .. I noticed I forgot the second x

  58. Nnesha
    • one year ago
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    yes right

  59. Destinyyyy
    • one year ago
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    Okay.. For the next one with the square root I have nothing.. I wasnt sure where to start

  60. Destinyyyy
    • one year ago
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    I can put it in a new question if youd like

  61. Nnesha
    • one year ago
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    which one ?

  62. Destinyyyy
    • one year ago
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    Ill tag you on it..

  63. Nnesha
    • one year ago
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    alright

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