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## anonymous one year ago very EASY and SIMPLE question! check~

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1. anonymous

$\frac{ 2x }{ x+4 } \times \frac{ 3x }{ 3x} = \frac{ 6x }{ 3x^2 + 12x }$ Why wouldn't this be right, I forgot?

2. Nnesha

you can simplify that remember it's 3x over 3x = ?

3. anonymous

no sorry I should have added more, 3 over 3 is my common denominator i'm using

4. anonymous

my bad about the confusion.

5. Nnesha

post the original question first plz

6. anonymous

alright one moment

7. anonymous

Here we are

8. anonymous

but i was told the answer was this? {7x^2 + 3x - 4}/{3x^2 + 12x}

9. Nnesha

only 3x isn't the common denominator both fractions hve different denominator so multiply them that would be the common denominator

10. anonymous

im so confused now

11. anonymous

This is what I was shown to do

12. anonymous

Answer

13. Nnesha

i'll give you an example $\frac{ a }{ b } +\frac{ c }{ d }$ b d both are common denominator

14. Nnesha

ahh i see so they divided into 2 step

15. Nnesha

$$\color{blue}{\text{Originally Posted by}}$$ @kaylaprincess $\frac{ 2x }{ x+4 } \times \frac{ 3x }{ 3x} = \frac{ 6x }{ 3x^2 + 12x }$ Why wouldn't this be right, I forgot? $$\color{blue}{\text{End of Quote}}$$ now multiply the numerator and denominator by x+4 so basically they separatd one step into 2

16. anonymous

$\frac{ 6x }{ 3x^2 + 12 } \times \frac{ x + 4 }{ x + 4 } =$

17. anonymous

like that?

18. Nnesha

yes right so 3x and x+4 both are common denominator

19. Nnesha

or one step $\huge\rm \frac{ 2x(3x)-(x-1)(x+4) }{ 3x(x+4)}$

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