## kaylaprincess one year ago very EASY and SIMPLE question! check~

1. kaylaprincess

$\frac{ 2x }{ x+4 } \times \frac{ 3x }{ 3x} = \frac{ 6x }{ 3x^2 + 12x }$ Why wouldn't this be right, I forgot?

2. Nnesha

you can simplify that remember it's 3x over 3x = ?

3. kaylaprincess

no sorry I should have added more, 3 over 3 is my common denominator i'm using

4. kaylaprincess

5. Nnesha

post the original question first plz

6. kaylaprincess

alright one moment

7. kaylaprincess

Here we are

8. kaylaprincess

9. Nnesha

only 3x isn't the common denominator both fractions hve different denominator so multiply them that would be the common denominator

10. kaylaprincess

im so confused now

11. kaylaprincess

This is what I was shown to do

12. kaylaprincess

13. Nnesha

i'll give you an example $\frac{ a }{ b } +\frac{ c }{ d }$ b d both are common denominator

14. Nnesha

ahh i see so they divided into 2 step

15. Nnesha

$$\color{blue}{\text{Originally Posted by}}$$ @kaylaprincess $\frac{ 2x }{ x+4 } \times \frac{ 3x }{ 3x} = \frac{ 6x }{ 3x^2 + 12x }$ Why wouldn't this be right, I forgot? $$\color{blue}{\text{End of Quote}}$$ now multiply the numerator and denominator by x+4 so basically they separatd one step into 2

16. kaylaprincess

$\frac{ 6x }{ 3x^2 + 12 } \times \frac{ x + 4 }{ x + 4 } =$

17. kaylaprincess

like that?

18. Nnesha

yes right so 3x and x+4 both are common denominator

19. Nnesha

or one step $\huge\rm \frac{ 2x(3x)-(x-1)(x+4) }{ 3x(x+4)}$