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kaylaprincess

  • one year ago

very EASY and SIMPLE question! check~

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  1. kaylaprincess
    • one year ago
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    \[\frac{ 2x }{ x+4 } \times \frac{ 3x }{ 3x} = \frac{ 6x }{ 3x^2 + 12x }\] Why wouldn't this be right, I forgot?

  2. Nnesha
    • one year ago
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    you can simplify that remember it's 3x over 3x = ?

  3. kaylaprincess
    • one year ago
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    no sorry I should have added more, 3 over 3 is my common denominator i'm using

  4. kaylaprincess
    • one year ago
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    my bad about the confusion.

  5. Nnesha
    • one year ago
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    post the original question first plz

  6. kaylaprincess
    • one year ago
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    alright one moment

  7. kaylaprincess
    • one year ago
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    Here we are

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  8. kaylaprincess
    • one year ago
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    but i was told the answer was this? {7x^2 + 3x - 4}/{3x^2 + 12x}

  9. Nnesha
    • one year ago
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    only 3x isn't the common denominator both fractions hve different denominator so multiply them that would be the common denominator

  10. kaylaprincess
    • one year ago
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    im so confused now

  11. kaylaprincess
    • one year ago
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    This is what I was shown to do

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  12. kaylaprincess
    • one year ago
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    Answer

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  13. Nnesha
    • one year ago
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    i'll give you an example \[\frac{ a }{ b } +\frac{ c }{ d }\] b d both are common denominator

  14. Nnesha
    • one year ago
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    ahh i see so they divided into 2 step

  15. Nnesha
    • one year ago
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    \(\color{blue}{\text{Originally Posted by}}\) @kaylaprincess \[\frac{ 2x }{ x+4 } \times \frac{ 3x }{ 3x} = \frac{ 6x }{ 3x^2 + 12x }\] Why wouldn't this be right, I forgot? \(\color{blue}{\text{End of Quote}}\) now multiply the numerator and denominator by x+4 so basically they separatd one step into 2

  16. kaylaprincess
    • one year ago
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    \[\frac{ 6x }{ 3x^2 + 12 } \times \frac{ x + 4 }{ x + 4 } = \]

  17. kaylaprincess
    • one year ago
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    like that?

  18. Nnesha
    • one year ago
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    yes right so 3x and x+4 both are common denominator

  19. Nnesha
    • one year ago
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    or one step \[\huge\rm \frac{ 2x(3x)-(x-1)(x+4) }{ 3x(x+4)}\]

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