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@Nnesha @iambatman @ganeshie8
A good way to do these problems is to graph it, so start with the original graph of y = tanx and apply the transformations.
I did. But it's kinda hard to tell what values are excluded.
Do you know if a TI-84 could tell me?
I just got one for my AP Calculus class, but I don't know how to use it.
I haven't used a TI 84 in a very long time, but you shouldn't need it. You can tell by the graph, so could you tell me the domain of y = tanx?
all real numbers except for kpi/2 ?
|dw:1441920593712:dw| this is y = tanx, lets keep it simple how can you defined the domain?
I know I'm not a very good artist :P but using a mouse isn't very helpful!
pi/2 is excluded, and then...well. its basically pi/2 + kpi right>
Okay, so will it be the same for the other equation, or different because of the transformations?
Sounds good, assuming k is an integer, now use your transformations and apply the same thing.
do i multiply it by 3?
1/3rd i mean? for stretch
It's the same as regular transformations, so don't let the trig functions scare you. But instead the terms are a bit different, so \[y = a f (b(x-h))+k\] in this case we say a is the amplitude and k is the vertical displacement. Remember amplitude is the distance from the mid to the max or from the mid to the min, so in the graph above |dw:1441921654850:dw|
Your mid would be the vertical displacement
Umm...since you'rer shifting it by pi, will it be 3pi/2 +kpi?
What is the period of your graph?
tanx is a bit tricky, notice that the period of the original graph is pi
oh, i was doing the other equation