## anonymous one year ago An atom emits a photon of wavelength 1.08 meters. What is the energy change occurring in the atom due to this emission? (Planck's constant is 6.626 × 10-34 joule seconds, the speed of light is 2.998 × 108 m/s) 7.1560 × 10-34 joules 1.8393 × 10-25 joules 2.3869 × 10-42 joules 1.9864 × 10-25 joules

1. anonymous

you can get the energy multiplying the frequency of the emitted light by Planck's constant: $$E=h\nu$$ since you are given the wavelength, $$\lambda$$, you will have to calculate the frequency, $$\nu$$, first using: $$\lambda=c\nu$$ where $$c$$ is the speed of light...

2. anonymous

give it a try and see if you can get the result!

3. anonymous

idk how to do it