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anonymous

  • one year ago

An atom emits a photon of wavelength 1.08 meters. What is the energy change occurring in the atom due to this emission? (Planck's constant is 6.626 × 10-34 joule seconds, the speed of light is 2.998 × 108 m/s) 7.1560 × 10-34 joules 1.8393 × 10-25 joules 2.3869 × 10-42 joules 1.9864 × 10-25 joules

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  1. anonymous
    • one year ago
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    you can get the energy multiplying the frequency of the emitted light by Planck's constant: \(E=h\nu\) since you are given the wavelength, \(\lambda\), you will have to calculate the frequency, \(\nu\), first using: \(\lambda=c\nu\) where \(c\) is the speed of light...

  2. anonymous
    • one year ago
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    give it a try and see if you can get the result!

  3. anonymous
    • one year ago
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    idk how to do it

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