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anonymous
 one year ago
Determine two pairs of polar coordinates for the point (2, 2) with 0° ≤ θ < 360°.
anonymous
 one year ago
Determine two pairs of polar coordinates for the point (2, 2) with 0° ≤ θ < 360°.

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MTALHAHASSAN2
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441922948541:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0would it be (2 square root of 2, 135°), (2 square root of 2, 315°)?

MTALHAHASSAN2
 one year ago
Best ResponseYou've already chosen the best response.0wait what are you trying to find??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.02 pairs of polar coordinates

MTALHAHASSAN2
 one year ago
Best ResponseYou've already chosen the best response.0@nanaruiz123 do you still need help??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ya i dont really get how to do this lol

MTALHAHASSAN2
 one year ago
Best ResponseYou've already chosen the best response.0@dtan5457 can you plz help

MTALHAHASSAN2
 one year ago
Best ResponseYou've already chosen the best response.0@nanaruiz123 this is the hard question thou

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0converting rectangular (x,y) to polar (r,θ) : \[r=\sqrt{x^2+y^2}\] \[\theta=\tan^{1} (\frac{ y }{ x})\] \[r=\sqrt{2^2+(2)^2}\]= \[2\sqrt{2}\] \[\theta=\tan^{1} (\frac{ 2 }{ 2})=315\] \[(2\sqrt{2},315)\] the other pair of polar coordinate with negative radius>>(r,θ+(2k+1)*180) let k=1 so the other pair \[(2\sqrt{2},135)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh my god thank you so much @ASAAD123

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0welcome ^_^ @nanaruiz123

MTALHAHASSAN2
 one year ago
Best ResponseYou've already chosen the best response.0woo nice job @ASAAD123
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