## anonymous one year ago Determine two pairs of polar coordinates for the point (2, -2) with 0° ≤ θ < 360°.

1. MTALHAHASSAN2

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2. anonymous

would it be (2 square root of 2, 135°), (-2 square root of 2, 315°)?

3. MTALHAHASSAN2

wait what are you trying to find??

4. anonymous

2 pairs of polar coordinates

5. MTALHAHASSAN2

oh ok

6. MTALHAHASSAN2

give me a sec

7. MTALHAHASSAN2

@chachi123

8. MTALHAHASSAN2

@nanaruiz123 do you still need help??

9. anonymous

ya i dont really get how to do this lol

10. MTALHAHASSAN2

@dtan5457 can you plz help

11. MTALHAHASSAN2

@Nnesha

12. MTALHAHASSAN2

13. MTALHAHASSAN2

@nanaruiz123 this is the hard question thou

14. anonymous

ya its pre-calc

15. anonymous

converting rectangular (x,y) to polar (r,θ) : $r=\sqrt{x^2+y^2}$ $\theta=\tan^{-1} (\frac{ y }{ x})$ $r=\sqrt{2^2+(-2)^2}$= $2\sqrt{2}$ $\theta=\tan^{-1} (\frac{ -2 }{ 2})=315$ $(2\sqrt{2},315)$ the other pair of polar coordinate with negative radius>>(-r,θ+(2k+1)*180) let k=-1 so the other pair $(-2\sqrt{2},135)$

16. anonymous

oh my god thank you so much @ASAAD123

17. anonymous

welcome ^_^ @nanaruiz123

18. MTALHAHASSAN2