if x+y=1 and x^2+y^2=4, what is x^3+y^3

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

if x+y=1 and x^2+y^2=4, what is x^3+y^3

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

weird precalc question i got today no idea how to do it

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

\[(x+y)^3 = x^3+3x^2y+3xy^2+y^3\] \[(x+y)^2 = x^2+2xy+y^2\] This should be all you need :)
im gonna give it try.
Sounds good, I'll give you some more hints if you need them later. :D
the formula is just the most simplfied versions of x^3+y^3=(x+y)(x^2-xy+y^2) right?
you have the formula. All you have to do is just input the given Info
im just confused on whether im suppose to use the x^3+Y^2 formula or (x+y)^3
(x+y)(x^2-xy+y^2)=(1)(4-xy)
\[(x+y)^3 = x^3+3x^2y+3xy^2+y^3\] \[(x+y)^3 = x^3+y^3 + 3xy(x+y)\] \[(x+y)^3 - 3xy(x+y)= x^3+y^3\] So I arranged it so we have \(x^3+y^3\) which is what we want, and we know that \(x+y=1\) so we plug it in now: \[1^3 - 3xy(1)=1-3xy = x^3+y^3\] What's xy? Let's use this: \[(x+y)^2 = x^2+2xy+y^2\] \[\frac{(x+y)^2 - (x^2+y^2)}{2} = xy\] \[\frac{1^2 - 4}{2} =\frac{-3}{2} = xy\] Now we can plug it in: \[1-3 \frac{-3}{2} = x^3+y^3\]
im seeing what you did but if I had started with the formula (x+y)(x^2-xy+y^2) if i plug in from there I get 4-xy? could i continue form here?
Yeah It looks like that'd probably work too
im not sure what to do from there though
do i use the same formula ?
Use(x+y)^2=x^2+2xy+y^2 from there
And solve for xy
Oh I think I got it. 1^2=4+2xy 1-4=-3 -3/2=2xy xy=-3/2 1(4-3/2)=x^3+y^3
can you check for me? and how would you know which formula to use? it seems like you would need more than 1 to compute all the variables
you will end up with ×y =-3/2 so (1) (4-xy)=4-(-3/2)= 4+3/2= x^3 + y^3
oh, dumb negative mistake by me. this is kind of confusing because i never substituted formulas to solve questions like this. normally, how would you know which formulas to use?
like how we used x^3+y^3 then to (x+y)^2?
Try to reason through it using the Known formulas
you are right. this is only my first question with this, i just need to practice more. thank you both so much.

Not the answer you are looking for?

Search for more explanations.

Ask your own question