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anonymous

  • one year ago

given f(x)=-x^2+2x, find f(-3) will medal and fan :3

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  1. Nnesha
    • one year ago
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    f(-3) that means x =-3 so substitute x for -3 into f(x)=-x^2+2x

  2. anonymous
    • one year ago
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    f(-3)=-3x^2+2(3)

  3. anonymous
    • one year ago
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    i didn't mean that x after 3...

  4. Nnesha
    • one year ago
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    alright it should be -(-3)^2+2(-3) now solve this

  5. anonymous
    • one year ago
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    -(-9)+-6

  6. Nnesha
    • one year ago
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    when you take even power of negative number you will always get positive answer

  7. anonymous
    • one year ago
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    so 9+6?

  8. Nnesha
    • one year ago
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    \[\huge\rm -\color{ReD}{x}^2+2\color{ReD}{x}\]this is the function replace x with -3 \[\huge\rm -(\color{ReD}{-3})^2+2(\color{ReD}{-3})\] 2 times -3 = ?

  9. anonymous
    • one year ago
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    -6

  10. Nnesha
    • one year ago
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    yes right \[-(-3)^2-6\] solve

  11. anonymous
    • one year ago
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    9-6=3

  12. Nnesha
    • one year ago
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    (-3)^2 = 9 there is a negative sign front of the parentheses

  13. anonymous
    • one year ago
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    but you said two negatives make a positive????

  14. Nnesha
    • one year ago
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    yes right so (-3)^2 = -3 times -3= 9

  15. anonymous
    • one year ago
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    i got 9 and i plugged it into the equation and that's how i got 3

  16. Nnesha
    • one year ago
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    \[\huge\rm\color{blue}{ -}\color{ReD}{x}^2+2\color{ReD}{x}\]this is the function replace x with -3 \[\huge\rm \color{blue}{-}(\color{ReD}{-3})^2+2(\color{ReD}{-3})\] \[\huge\rm \color{blue}{-}(\color{ReD}{9})-6\] (-3)^2 =9 but i'm saying blue sign would stay there

  17. Nnesha
    • one year ago
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    |dw:1441923429502:dw|

  18. anonymous
    • one year ago
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    ohh okay i see what you're saying now..

  19. anonymous
    • one year ago
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    do you -(9)-6? or is that the answer?

  20. Nnesha
    • one year ago
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    yes right

  21. anonymous
    • one year ago
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    Thank you

  22. Nnesha
    • one year ago
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    \(\color{blue}{\text{Originally Posted by}}\) @Justmeneedinghelp do you -(9)-6? or is that the answer? \(\color{blue}{\text{End of Quote}}\) yes solve that

  23. Nnesha
    • one year ago
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    np

  24. anonymous
    • one year ago
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    @Nnesha i got -15 is that right?

  25. Nnesha
    • one year ago
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    yes right

  26. anonymous
    • one year ago
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    okii thanks again

  27. Nnesha
    • one year ago
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    yw

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