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have you tried using the formula for finding the angle between two vectors?

solve for theta
\[\cos(\theta)=\frac{ u \cdot v}{|u||v|}\]

cos(theta) = 6 * 7 / |-1| |-4| ?

how did you get that?

dot product: 42 + 4 = 46
magnitude: 36 + 1 = 37 = 6.08
?

you still need to find |v|

i took the square root of 36 + 1 and got 6.08
do i find |v| then same way?

49 + 16 = 65
square root = 8.06

sqrt(49+16)=sqrt(65) then this will be correct

\[u \cdot v=46 \\ |u|=\sqrt{37} \\ |v|=\sqrt{65}\]

enter this into the formula I gave above and solve for theta

I even summarized these values above

cos(theta) = 46 / √37 √65

oh, okay.. i see

last step solve for theta
theta is the angle after all

i got 60.96..

i see, so it would be 20.3 degrees

yeah i know, i found out what i did wrong.

well that's great

thank you so much for your help! you are awesome!

it was no problem