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anonymous

  • one year ago

An arrow was shot straight up with an initial seed of 50.0m/s. what was the maximum height that the arrow flew?

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  1. IrishBoy123
    • one year ago
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    use the equations of motion, specifically \[v^2 = u^2 + 2 \ a \ x\] \[\rightarrow x = \frac{v^2 - u^2}{2a}\] u = 50, v = 0, a = -10

  2. anonymous
    • one year ago
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    how is a = -10? shouldn't it be -9.8 m/s^2?

  3. Abhisar
    • one year ago
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    Yes, but in order to simplify the calculation you can say that a = -9.8 \(\sf m/s^2\) \(\approx\) -10 \(\sf m/s^2\)

  4. rvc
    • one year ago
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    yep the above equation will lead you to your answer

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