## anonymous one year ago An arrow was shot straight up with an initial seed of 50.0m/s. what was the maximum height that the arrow flew?

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1. IrishBoy123

use the equations of motion, specifically $v^2 = u^2 + 2 \ a \ x$ $\rightarrow x = \frac{v^2 - u^2}{2a}$ u = 50, v = 0, a = -10

2. anonymous

how is a = -10? shouldn't it be -9.8 m/s^2?

3. Abhisar

Yes, but in order to simplify the calculation you can say that a = -9.8 $$\sf m/s^2$$ $$\approx$$ -10 $$\sf m/s^2$$

4. rvc