If x+1/x=7, compute x^3+1/x^2

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If x+1/x=7, compute x^3+1/x^2

Mathematics
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So far I have x^2+1=7x x^2=7x-1 x^3+1/7x-1 x^2x/(1)+1/(7x-1) when I cross out 7x-1 i get x+1. then what?
Hang on a min.

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Other answers:

okay thanks
( x+1)/x=7 multiply both sides by × x +1 =7x Subtract × from both sides 1=6x x= 1/6
Plug × to other expression
wait so all my x^2+1=7x was incorrect?
. Is the original problem you posted correct as written?
\[x+\frac{ 1 }{ x }=7, x^3+\frac{ 1 }{ x^2 }=?\]
± see, Better you use later to post from now on.
latex *
okay
so does your solution still stand?
No, it doesn't
any ideas?
Calculate ( x +1/ x ) ^ 2 and (x+1 / x ) ^ 3 )
i dont get it sorry
one of my friends even said its unsolvable without quadratic formula but im pretty sure my teacher doesnt want a quadratic use
( x + 1 / x ) ^ 2 = 7^2
If you don't get that I can't help you
Expand the left side
\[x^2+\frac{ 1 }{ x^2 }+x+\frac{ 1 }{ x^2 }\]
That's not what I got
lol i give up, i'll ask my teacher tomorrow. thanks
You give up too easy.
Been working on 4 problems for about 2 hours, it's time too move on if I want decently sufficient sleep. I've been getting mixed answers and solutions so I'll just let my teacher explain.
it can be solved with the quadratic formula so I just used that. Not sure if that's what my teacher wants but i'll see.
Nope, it probably isn't. There's another way to solve that your teacher may be looking for.

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