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anonymous
 one year ago
An object with a mass of 7.5g raises the water level in the cylinder from 25.1mL to 30.1mL. What is the density of the object
anonymous
 one year ago
An object with a mass of 7.5g raises the water level in the cylinder from 25.1mL to 30.1mL. What is the density of the object

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taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.0Density=mass divided by the final volume

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Alexa_Noelle33 What do you think the volume of the object is ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\sf \rho = \frac{m}{v}~~~~~~~~~~~~~~\rho = density \]\[\sf \rho = \frac{m_{obj}}{\Delta v}~~~~~~~~~\Delta v = change ~in~volume~of~water\]\[\sf \rho = \frac{7.5~g}{(30.1~ml ~~25.1~ml)}~ =~? ~~\frac{g}{mL}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The initial volume was 25.1mL and then the object of the mass which is 7.5g raised the final volume to 30.1mL. Looking for the density. Density =m/v. Mass given=7.5g. Water level before object submerged =25.1mL. Water level after submerged =30.2mL. Need density (g/mL). 30.1mL25.1mL=5mL. 7.5g/5mL= 1.5g/mL.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(\color{#0cbb34}{\text{Originally Posted by}}\) @mbamelun The initial volume was 25.1mL and then the object of the mass which is 7.5g raised the final volume to 30.1mL. Looking for the density. Density =m/v. Mass given=7.5g. Water level before object submerged =25.1mL. \(\sf \color{red}{Water ~level ~after ~submerged =30.2mL}\). Need density (g/mL). 30.1mL25.1mL=5mL. 7.5g/5mL= 1.5g/mL. \(\color{#0cbb34}{\text{End of Quote}}\) Typo there. :P
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