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Albert0898

  • one year ago

if x^2-y^2=12 and x-y=4 what is the value of x^2+2xy+y^2 a. 3 b. 8 c. 9 d. 12 e. 16

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  1. myininaya
    • one year ago
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    you could factor x^2-y^2 and then use what x-y is equal to to find x+y

  2. myininaya
    • one year ago
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    then recall x^2+2xy+y^2 can be written as (x+y)^2

  3. Albert0898
    • one year ago
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    Erm.... Well here's what I did so far... I did (x-y)^2 and got x^2 - 2xy + y^2 = 16 I don't know what else to do

  4. myininaya
    • one year ago
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    well can you try what I said?

  5. myininaya
    • one year ago
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    x^2-y^2 can be factored

  6. myininaya
    • one year ago
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    it is a difference of squares

  7. myininaya
    • one year ago
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    you are given the value of x-y this will allow you to find x+y

  8. myininaya
    • one year ago
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    and then all you have to do after finding x+y is find (x+y)^2

  9. myininaya
    • one year ago
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    So have you factored x^2-y^2 yet?

  10. Albert0898
    • one year ago
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    (x-y)(x+y)

  11. myininaya
    • one year ago
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    \[x^2-y^2=12 \\ (x-y)(x+y)=12 \\ \text{ you are given } x-y=4 \\ \text{ just plug in } \\ 4(x+y)=12\] \[\text{ and you want to find } (x+y)^2\]

  12. Albert0898
    • one year ago
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    Ahh!! Now I understand it. Thank you!

  13. myininaya
    • one year ago
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    k great

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