Albert0898
  • Albert0898
if x^2-y^2=12 and x-y=4 what is the value of x^2+2xy+y^2 a. 3 b. 8 c. 9 d. 12 e. 16
Mathematics
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SOLVED
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jamiebookeater
  • jamiebookeater
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myininaya
  • myininaya
you could factor x^2-y^2 and then use what x-y is equal to to find x+y
myininaya
  • myininaya
then recall x^2+2xy+y^2 can be written as (x+y)^2
Albert0898
  • Albert0898
Erm.... Well here's what I did so far... I did (x-y)^2 and got x^2 - 2xy + y^2 = 16 I don't know what else to do

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myininaya
  • myininaya
well can you try what I said?
myininaya
  • myininaya
x^2-y^2 can be factored
myininaya
  • myininaya
it is a difference of squares
myininaya
  • myininaya
you are given the value of x-y this will allow you to find x+y
myininaya
  • myininaya
and then all you have to do after finding x+y is find (x+y)^2
myininaya
  • myininaya
So have you factored x^2-y^2 yet?
Albert0898
  • Albert0898
(x-y)(x+y)
myininaya
  • myininaya
\[x^2-y^2=12 \\ (x-y)(x+y)=12 \\ \text{ you are given } x-y=4 \\ \text{ just plug in } \\ 4(x+y)=12\] \[\text{ and you want to find } (x+y)^2\]
Albert0898
  • Albert0898
Ahh!! Now I understand it. Thank you!
myininaya
  • myininaya
k great

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