if x^2-y^2=12 and x-y=4 what is the value of x^2+2xy+y^2 a. 3 b. 8 c. 9 d. 12 e. 16

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if x^2-y^2=12 and x-y=4 what is the value of x^2+2xy+y^2 a. 3 b. 8 c. 9 d. 12 e. 16

Mathematics
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you could factor x^2-y^2 and then use what x-y is equal to to find x+y
then recall x^2+2xy+y^2 can be written as (x+y)^2
Erm.... Well here's what I did so far... I did (x-y)^2 and got x^2 - 2xy + y^2 = 16 I don't know what else to do

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well can you try what I said?
x^2-y^2 can be factored
it is a difference of squares
you are given the value of x-y this will allow you to find x+y
and then all you have to do after finding x+y is find (x+y)^2
So have you factored x^2-y^2 yet?
(x-y)(x+y)
\[x^2-y^2=12 \\ (x-y)(x+y)=12 \\ \text{ you are given } x-y=4 \\ \text{ just plug in } \\ 4(x+y)=12\] \[\text{ and you want to find } (x+y)^2\]
Ahh!! Now I understand it. Thank you!
k great

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