A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
MEDAL!!
(refer to choosing two cards from a thoroughly shuffled deck. Assume that the deck is shuffled after a card is returned to the deck)
If you put the first card back in the deck before you draw the next, what is the probability that the first card is a 10 and the second card is a jack?
anonymous
 one year ago
MEDAL!! (refer to choosing two cards from a thoroughly shuffled deck. Assume that the deck is shuffled after a card is returned to the deck) If you put the first card back in the deck before you draw the next, what is the probability that the first card is a 10 and the second card is a jack?

This Question is Closed

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1Focus on one card at a time. What is the probability of pulling out a "10" card ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1here's a visual of all the cards (52 total; 4 suits, 13 per suit) http://www.jfitz.com/cards/classicplayingcards.png

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hmm, there are four 10s

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1yes, so the probability of picking a single 10 is?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0guessing 4 out of 52

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1you can reduce that fraction to get ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1so if you focus on one suit only, there is a 1 in 13 chance to get a "10" card

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1next step: find the probability of picking a jack. All 52 cards are still there since the first card was put back (it says `Assume that the deck is shuffled after a card is returned to the deck`)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0if there are 4 jacks wouldn't it be 4/52=1/13 again?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1now multiply the two fractions

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1P(10 on first draw, jack on second draw) = P(10 on first draw) * P(jack on second draw) this works because the two events are independent

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0multiplying the two fractions would get me 1/169

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1which is the correct final answer
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.