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anonymous
 one year ago
which sets of ordered pairs represent functions from a to b , A={u,v,w} and B={2,1,0,1,2}
anonymous
 one year ago
which sets of ordered pairs represent functions from a to b , A={u,v,w} and B={2,1,0,1,2}

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can you please help @mathmate

mathmate
 one year ago
Best ResponseYou've already chosen the best response.2There are many possible answers. If you have answer choices, choose the choices where there is no repetition in the set A, i.e. u, v, w appear at most once in the set of ordered pairs. This is because a function can only have one single value of the image given a value of the preimage.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the choices are (a) {(v,1) , (u,2) , (w,0) , (u,2)} (b) (u,2) , (v,2) , (w,1) (c) (u,2) , (v,0) , (w,2)

mathmate
 one year ago
Best ResponseYou've already chosen the best response.2Please try to understand my previous post, and reread if necessary. You will have no problem making your choices. :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i had missed out one of the answer choices and it happened to be the right one

mathmate
 one year ago
Best ResponseYou've already chosen the best response.2If we examine each of the answers choices, (a) {(v,1) , (u,2) , (w,0) , (u,2)} (b) (u,2) , (v,2) , (w,1) (c) (u,2) , (v,0) , (w,2) For the relation {(v,1) , (u,2) , (w,0) , (u,2)} Ask yourself, what would be the value of f(v)? It is clear that f(v)=1 because the ordered pair (v,1) tells us that. However, what is the value of f(u)? There are two ordered pairs, (u,2), and (u,2). We do not know which one is true. A relation that contains ambiguities like this is NOT considered a function. So this relation is not a function. For both of the following relations, (u,2) , (v,2) , (w,1) (u,2) , (v,0) , (w,2) the ambiguity does not exist, given any value of u, v or w, we can find a UNIQUE value of the image, so both are functions.
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