## anonymous one year ago Help me please? Simplify the following:

1. anonymous

$\sqrt{108x4y9}$

2. anonymous

I think you mean? $\sqrt{108x^4y^9}$ find a perfect square factor in 108 first. You can split 108 to 36 and 3, and 36 is a square. So take the square root of 36 and put it outside the square root. $6 * \sqrt{3x^4y^9}$

3. anonymous

than, take the square root of even exponents out. Odd exponents, leave one inside. $6 * x^2 * y^4 \sqrt{3y}$

4. anonymous

so $6x^2y^4\sqrt{3y}$