wintersuntime
  • wintersuntime
Can someone be nice enough to help me please ?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Whats the question?
wintersuntime
  • wintersuntime
http://westada.org/cms/lib8/ID01904074/Centricity/Domain/793/3.7%20What%20Comes%20Next.Later.pdf
wintersuntime
  • wintersuntime
I need help with function A and B

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wintersuntime
  • wintersuntime
@peachpi
anonymous
  • anonymous
look at the y's to figure out the pattern. What are they doing to get to the next number? Think in terms of addition and multiplication
wintersuntime
  • wintersuntime
multiplying by 2
anonymous
  • anonymous
right, so that's the answer to #1
wintersuntime
  • wintersuntime
For number 2 what it be f(x) = f(n-1) x 2
anonymous
  • anonymous
For the recursive formula, the first thing is to write the first term. It looks like they're using function notations, so start with f(1). y is 5 when x is 1, so the first part is \[f(1)=5\] Then since it's multiplying by 2, \[f(n)=2f(n-1)\]
anonymous
  • anonymous
make sense?
wintersuntime
  • wintersuntime
So it would only be f(n)= 2f(n-1)
anonymous
  • anonymous
no, you need to keep f(1) = 5 as well. The recursive formula only gives you a term if you know the previous term
wintersuntime
  • wintersuntime
so f(1)=5 2f(n-1)
anonymous
  • anonymous
yes
anonymous
  • anonymous
actually, no
wintersuntime
  • wintersuntime
between 5 and 2 i don't put nothing ?
anonymous
  • anonymous
Write it like this \[f(1)=5, f(n)=2f(n-1)\]
wintersuntime
  • wintersuntime
oh it was like that
anonymous
  • anonymous
It's saying that the first term is 5. Then to find the second term, multiply the first one by 2. Then to find the third term, multiply the second by 2. and so on. So with a recursive formula, if you want to know the 67th term, you have to know the 66th. But to know the 66th, you have to know the 65th and so on. It's only useful to point out the pattern. Not really useful for anything else
anonymous
  • anonymous
The explicit one is the useful one. \[f(n)=ar^{n-1}\] a = first term r = number you multiply by (called the common ratio) Plug in your numbers to that formula to get the explicit formula
wintersuntime
  • wintersuntime
so i plug in 65?
anonymous
  • anonymous
no, your first term is 5, and you're multiplying by 2. So plug in 5 for a and 2 for r to get the formula
anonymous
  • anonymous
\[f(n)=5(2)^{n-1}\]
wintersuntime
  • wintersuntime
oh
anonymous
  • anonymous
the function for A is geometric because it's multiplying by the same number to get to the next term.
wintersuntime
  • wintersuntime
Isn't it geometric
anonymous
  • anonymous
yeah geometric
anonymous
  • anonymous
I gtg. sorry I can't stay to help on the next one
wintersuntime
  • wintersuntime
its okay

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