anonymous
  • anonymous
5(2+4z)=85
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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pooja195
  • pooja195
Are we solving for z?
anonymous
  • anonymous
yea
pooja195
  • pooja195
Start with this \[\huge~\rm~(5)(2)+(5)(4z)=85(Distribute) \]

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More answers

pooja195
  • pooja195
Whats 5 x 2 = ?
anonymous
  • anonymous
10
pooja195
  • pooja195
\[\huge~\rm~10+(5)(4z)=85(Distribute)\] whats 5 x 4 = ?
anonymous
  • anonymous
20
pooja195
  • pooja195
\[ \huge~\rm~10+20z=85\] any ideas on what to do next?
anonymous
  • anonymous
nope
anonymous
  • anonymous
do you add 10+20z
pooja195
  • pooja195
Since we are solving for z we need to subtract 10 from both sides \[\huge~\rm~10-10+20z=85+10\]
pooja195
  • pooja195
\[\huge~\rm~20z=85+10=?\]
anonymous
  • anonymous
95?
pooja195
  • pooja195
wait we were supposed to subtract 10 >.< sorry!! 85-10=?
anonymous
  • anonymous
75
pooja195
  • pooja195
ok 20z=75 divide both sides by 20 20/20=1 right so that leaves use with z z=75/20 what is 75/20?
anonymous
  • anonymous
3.75
pooja195
  • pooja195
Yep OR we can also say z=15/4
pooja195
  • pooja195
\(~~~~~~~~~~~~~~~~~~~~~~~~~~\Huge{\color{red}{\heartsuit}\color{orange}{\bigstar}\color{yellow}{\heartsuit}\color{green}{\bigstar}\color{blue}{\heartsuit}\color{purple}{\bigstar}\color{hotpink}{\heartsuit}}\)\(\Huge\bf\color{#FF0000}W\color{#FF4900}e\color{#FF9200}l\color{#FFDB00}c\color{#FFff00}o\color{#B6ff00}m\color{#6Dff00}e\color{#24ff00}~\color{#00ff00}t\color{#00ff49}o\color{#00ff92}~\color{#00ffDB}O\color{#00ffff}p\color{#00DBff}e\color{#0092ff}n\color{#0049ff}S\color{#0000ff}t\color{#2400ff}u\color{#6D00ff}d\color{#B600ff}y\color{#FF00ff}!\)\(~~~~~~~~~~~~~~~~~~~~~~~~~~\Huge{\color{red}{\heartsuit}\color{orange}{\bigstar}\color{yellow}{\heartsuit}\color{green}{\bigstar}\color{blue}{\heartsuit}\color{purple}{\bigstar}\color{hotpink}{\heartsuit}}\)\(\Large\bf\color{Lime}{Please,\ don't\ hesitate\ to\ ask\ questions!}\)\(\Large\bf\color{magenta}{We're\ here\ to\ help!}\Large\color{magenta}{\ddot\smile}\)
anonymous
  • anonymous
ok thx
pooja195
  • pooja195
:)

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