I made an equation and I know the equation will work for it but I need to find out what x equals. 500=[2pi(x/2)]2+x

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I made an equation and I know the equation will work for it but I need to find out what x equals. 500=[2pi(x/2)]2+x

Mathematics
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\[500=\big[2\pi(x/2)\big]^2+x\]
Oops my bad hold on i'll write it correctly.
\[500=[2\pi(x/2)]2+x\]

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so it's times 2 not to the power of 2
oh \[500=\big[2\pi(x/2)\big]\times2+x\]
not sure what to do after I divide both sides by 2
Yup
lets look at this bit first \[[2π(x/2)]× 2\], can you simplify this
not sure what I did was I divided both sides by 2 to get rid of the 2 but I don't think that was right
\[4\pi(x/2)\]
Yes, \[[2π(x/2)]×2=4\pi (x/2)\] now, simplify again \[=\]
(combine the 4 and the /2 )
\[2pix\]
yeah so you have \[500=\big[2\pi(x/2)\big]\times2+x\\ 500= 2\pi x+x\]
now can you see a common factor in the right hand side ?
Oh ok that makes sense I got ti from here thanks a bunch!

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