## anonymous one year ago I made an equation and I know the equation will work for it but I need to find out what x equals. 500=[2pi(x/2)]2+x

1. UnkleRhaukus

$500=\big[2\pi(x/2)\big]^2+x$

2. anonymous

Oops my bad hold on i'll write it correctly.

3. anonymous

$500=[2\pi(x/2)]2+x$

4. anonymous

so it's times 2 not to the power of 2

5. UnkleRhaukus

oh $500=\big[2\pi(x/2)\big]\times2+x$

6. anonymous

not sure what to do after I divide both sides by 2

7. anonymous

Yup

8. UnkleRhaukus

lets look at this bit first $[2π(x/2)]× 2$, can you simplify this

9. anonymous

not sure what I did was I divided both sides by 2 to get rid of the 2 but I don't think that was right

10. anonymous

$4\pi(x/2)$

11. UnkleRhaukus

Yes, $[2π(x/2)]×2=4\pi (x/2)$ now, simplify again $=$

12. UnkleRhaukus

(combine the 4 and the /2 )

13. anonymous

$2pix$

14. UnkleRhaukus

yeah so you have $500=\big[2\pi(x/2)\big]\times2+x\\ 500= 2\pi x+x$

15. UnkleRhaukus

now can you see a common factor in the right hand side ?

16. anonymous

Oh ok that makes sense I got ti from here thanks a bunch!