## anonymous one year ago (X-2)^1/2=5 Solve

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1. Nnesha

you can convert 1/2 exponent to square root $\huge\rm [x^\frac{ 1 }{ 2 }=\sqrt{x}$

2. Nnesha

ignore [

3. Nnesha

so (x-2)^1/2 is same as $\sqrt{x-2} =5$ take square both sides to cancel out the square root

4. Nnesha

$\huge\rm (x-2)^\frac{ 1 }{ 2 }=5$ or keep the 1/2 exponent same thing now take square both sides $\huge\rm ((x-2)^\frac{ 1 }{ 2 })^2=(5)^2$

5. Nnesha

any question :? understand or not ? let me know what you get after that

6. anonymous

Oh ok now I see I got it. What about if the exponent us 1/3

7. Nnesha

remember the exponent rule $\huge\rm x^\frac{ m }{ n }=\sqrt[n]{x^m}$ denominator of the fraction would represent index

8. Nnesha

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