Precalculus help please?

- anonymous

Precalculus help please?

- katieb

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- anonymous

##### 1 Attachment

- jim_thompson5910

Draw a vertical line through x = -2
where does this vertical line cross the red curve?

- anonymous

I already know part a is 1, -1, 3, 4 but I don't understand part b, c, or d

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## More answers

- jim_thompson5910

b)
the domain is the set of allowed x values
so basically you state all of the x coordinates of each point as one big set

- jim_thompson5910

the range is the possible set of y values that can be outputs of the function

- jim_thompson5910

does that make sense?

- anonymous

So the domain is [-3,4]?

- anonymous

and the range is [-1,4]?

- jim_thompson5910

very nice

- jim_thompson5910

both are correct

- anonymous

okay, what about part c and d?

- jim_thompson5910

h(x) = 3 is the same as saying y = 3
draw a horizontal line through y = 3. Where does it cross the red curve?

- anonymous

2

- jim_thompson5910

I see two points. What are those points?

- anonymous

oh, -3 also

- anonymous

so would I just write -3 and 2? Or is there a special notation?

- jim_thompson5910

well they just want x values, so that works

- jim_thompson5910

actually there's one point I missed

- anonymous

4?

- jim_thompson5910

yeah so if the input is x = -3, x = 2, or x = 4, then the output is 3

- anonymous

okay, and for part d is it -3, -2, 0, 2, 4?

- jim_thompson5910

you'll need to use inequalities here

- anonymous

um okay, so -3<=x<=2 and x=4?

- jim_thompson5910

much better

- anonymous

Thank you so much @jim_thompson5910 ! You've been helping me with math for years and I'm in college now and my Professor speaks very broken English :(

- jim_thompson5910

I'm glad to be of help, and I'm sorry you and your teacher have a communication gap

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