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anonymous

  • one year ago

Simplify.

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    @ganeshie8 @Michele_Laino @Ashleyisakitty @triciaal @paki

  3. anonymous
    • one year ago
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    @Astrophysics @Nnesha

  4. paki
    • one year ago
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    do you know how do we take LCM...?

  5. anonymous
    • one year ago
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    i got x(x+2)/4 as my answer but thats not an option

  6. paki
    • one year ago
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    that's LCM...?

  7. anonymous
    • one year ago
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    idk

  8. paki
    • one year ago
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    |dw:1441948326037:dw|

  9. anonymous
    • one year ago
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    i got the same answer

  10. paki
    • one year ago
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    ok tell me, what will be the next step then....? how you will solve above equation...?

  11. anonymous
    • one year ago
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    |dw:1441948550384:dw|

  12. paki
    • one year ago
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    no... not like this... we can only add SIMILAR terms... like we can add x^2... as they are similar....

  13. paki
    • one year ago
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    |dw:1441948649645:dw|

  14. paki
    • one year ago
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    like here x^2 + x^2 will be 2X^2

  15. anonymous
    • one year ago
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    |dw:1441948846247:dw|

  16. paki
    • one year ago
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    yeah that's correct now.... nice work... :) 2x^2 + 4x / 8 is the answer :)

  17. anonymous
    • one year ago
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    would it have been easier to just pick that one cause it was the only one with 8 as the denominator?

  18. paki
    • one year ago
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    yeah, so B is the best option as per your options here...

  19. anonymous
    • one year ago
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    thx

  20. Nnesha
    • one year ago
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    \[\huge\rm \frac{ 2x^2+4x }{ 8 }\] you can amplify this 2 is common at the numerator so take it out \[\huge\rm \frac{ 2(x^2+2x) }{ 8 }\] now reduce the fraction 2/8= ? that would be ur answer

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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