## anonymous one year ago CHECK MY ANSWER?

1. anonymous

for WHAT?!?!?!?!

2. anonymous

It's either y = 0 or, y = x - 2

3. anonymous

not sure...

4. anonymous

:'( i don't know this type of math.

5. anonymous

no worries.

6. inkyvoyd

did you do polynomial/synthetic division? look at the remainder

7. steve816

It's y = x-6

8. steve816

oblique asymptotes can't be horizontal.

9. anonymous

didn't think I could $\frac{ (x-2)(x-2) }{ x }$

10. inkyvoyd

you factored that miserably wrong.

11. anonymous

jeeeezzz lol

12. inkyvoyd

x^2-4x+8 doesn't have rational roots.

13. anonymous

i know i know cause x + 2 is stuck together lol

14. inkyvoyd

It does have complex roots, but that is beside the point. The proper way to do thsi problem is to do polynomial or synthetic division.

15. inkyvoyd

what is x^2-4x+8 divided by x+2?

16. anonymous

synthetic <3

17. anonymous

lemme do it right now :-)

18. steve816

You have to use synthetic division. Khan academy has a great video on it.

19. anonymous

im so dumb WHY did I not see to use synthetic division lolllll @ me this is embarrassing

20. inkyvoyd

after doing the division you should come to the same conclusion as steve

21. anonymous

thank you everyone lol

22. inkyvoyd

and I was wrong before, it is not the remainder you are interested in. it is the quotient.

23. anonymous

correctttt didnt catch that

24. inkyvoyd

because for any remainder 1/(x^2-a) as x approaches infinity, the expression becomes zero and you are left with just the quotient.

25. anonymous

isnt this so fun

26. inkyvoyd

or really 1/(polynomial in x)

27. inkyvoyd

it is great review for me, surely :)

28. anonymous

got x -6! Thankkk you

29. inkyvoyd

:)

30. anonymous

need more coffee brain is failingg