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for WHAT?!?!?!?!

It's either y = 0 or, y = x - 2

not sure...

:'(
i don't know this type of math.

no worries.

did you do polynomial/synthetic division? look at the remainder

It's y = x-6

oblique asymptotes can't be horizontal.

didn't think I could \[\frac{ (x-2)(x-2) }{ x }\]

you factored that miserably wrong.

jeeeezzz lol

x^2-4x+8 doesn't have rational roots.

i know i know cause x + 2 is stuck together lol

what is x^2-4x+8 divided by x+2?

synthetic <3

lemme do it right now :-)

You have to use synthetic division. Khan academy has a great video on it.

im so dumb WHY did I not see to use synthetic division lolllll @ me this is embarrassing

after doing the division you should come to the same conclusion as steve

thank you everyone lol

and I was wrong before, it is not the remainder you are interested in. it is the quotient.

correctttt didnt catch that

isnt this so fun

or really 1/(polynomial in x)

it is great review for me, surely :)

got x -6! Thankkk you

:)

need more coffee brain is failingg