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for WHAT?!?!?!?!
It's either y = 0 or, y = x - 2
not sure...

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Other answers:

:'( i don't know this type of math.
no worries.
did you do polynomial/synthetic division? look at the remainder
It's y = x-6
oblique asymptotes can't be horizontal.
didn't think I could \[\frac{ (x-2)(x-2) }{ x }\]
you factored that miserably wrong.
jeeeezzz lol
x^2-4x+8 doesn't have rational roots.
i know i know cause x + 2 is stuck together lol
It does have complex roots, but that is beside the point. The proper way to do thsi problem is to do polynomial or synthetic division.
what is x^2-4x+8 divided by x+2?
synthetic <3
lemme do it right now :-)
You have to use synthetic division. Khan academy has a great video on it.
im so dumb WHY did I not see to use synthetic division lolllll @ me this is embarrassing
after doing the division you should come to the same conclusion as steve
thank you everyone lol
and I was wrong before, it is not the remainder you are interested in. it is the quotient.
correctttt didnt catch that
because for any remainder 1/(x^2-a) as x approaches infinity, the expression becomes zero and you are left with just the quotient.
isnt this so fun
or really 1/(polynomial in x)
it is great review for me, surely :)
got x -6! Thankkk you
:)
need more coffee brain is failingg

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