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- kaylaprincess

CHECK MY ANSWER?

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- anonymous

for WHAT?!?!?!?!

- kaylaprincess

It's either y = 0 or, y = x - 2

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- kaylaprincess

not sure...

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## More answers

- anonymous

:'(
i don't know this type of math.

- kaylaprincess

no worries.

- inkyvoyd

did you do polynomial/synthetic division? look at the remainder

- steve816

It's y = x-6

- steve816

oblique asymptotes can't be horizontal.

- kaylaprincess

didn't think I could \[\frac{ (x-2)(x-2) }{ x }\]

- inkyvoyd

you factored that miserably wrong.

- kaylaprincess

jeeeezzz lol

- inkyvoyd

x^2-4x+8 doesn't have rational roots.

- kaylaprincess

i know i know cause x + 2 is stuck together lol

- inkyvoyd

It does have complex roots, but that is beside the point. The proper way to do thsi problem is to do polynomial or synthetic division.

- inkyvoyd

what is x^2-4x+8 divided by x+2?

- kaylaprincess

synthetic <3

- kaylaprincess

lemme do it right now :-)

- steve816

You have to use synthetic division. Khan academy has a great video on it.

- kaylaprincess

im so dumb WHY did I not see to use synthetic division lolllll @ me this is embarrassing

- inkyvoyd

after doing the division you should come to the same conclusion as steve

- kaylaprincess

thank you everyone lol

- inkyvoyd

and I was wrong before, it is not the remainder you are interested in. it is the quotient.

- kaylaprincess

correctttt didnt catch that

- inkyvoyd

because for any remainder 1/(x^2-a) as x approaches infinity, the expression becomes zero and you are left with just the quotient.

- kaylaprincess

isnt this so fun

- inkyvoyd

or really 1/(polynomial in x)

- inkyvoyd

it is great review for me, surely :)

- kaylaprincess

got x -6! Thankkk you

- inkyvoyd

:)

- kaylaprincess

need more coffee brain is failingg

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