## kaylaprincess one year ago CHECK MY ANSWER?

1. anonymous

for WHAT?!?!?!?!

2. kaylaprincess

It's either y = 0 or, y = x - 2

3. kaylaprincess

not sure...

4. anonymous

:'( i don't know this type of math.

5. kaylaprincess

no worries.

6. inkyvoyd

did you do polynomial/synthetic division? look at the remainder

7. steve816

It's y = x-6

8. steve816

oblique asymptotes can't be horizontal.

9. kaylaprincess

didn't think I could $\frac{ (x-2)(x-2) }{ x }$

10. inkyvoyd

you factored that miserably wrong.

11. kaylaprincess

jeeeezzz lol

12. inkyvoyd

x^2-4x+8 doesn't have rational roots.

13. kaylaprincess

i know i know cause x + 2 is stuck together lol

14. inkyvoyd

It does have complex roots, but that is beside the point. The proper way to do thsi problem is to do polynomial or synthetic division.

15. inkyvoyd

what is x^2-4x+8 divided by x+2?

16. kaylaprincess

synthetic <3

17. kaylaprincess

lemme do it right now :-)

18. steve816

You have to use synthetic division. Khan academy has a great video on it.

19. kaylaprincess

im so dumb WHY did I not see to use synthetic division lolllll @ me this is embarrassing

20. inkyvoyd

after doing the division you should come to the same conclusion as steve

21. kaylaprincess

thank you everyone lol

22. inkyvoyd

and I was wrong before, it is not the remainder you are interested in. it is the quotient.

23. kaylaprincess

correctttt didnt catch that

24. inkyvoyd

because for any remainder 1/(x^2-a) as x approaches infinity, the expression becomes zero and you are left with just the quotient.

25. kaylaprincess

isnt this so fun

26. inkyvoyd

or really 1/(polynomial in x)

27. inkyvoyd

it is great review for me, surely :)

28. kaylaprincess

got x -6! Thankkk you

29. inkyvoyd

:)

30. kaylaprincess

need more coffee brain is failingg