tayaiv
  • tayaiv
Simultaneous equations: 6 = b√ 2 3a = b How can I find a?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
zpupster
  • zpupster
\[6=b \sqrt{2}\] divide both sides by sqrt 2 then you have b plug it in the 3a = b then divide both sides by 3 now you have a
tayaiv
  • tayaiv
What happens to 6 in the first equation when both sides are divided by sqrt 2? Why is only b left?
anonymous
  • anonymous
What you have to get is that algebra is like a set of scales. Whatever you do to one side of an equation you do to the other, and the only way to solve for a is to find b. We know 6 = b *sqrt(2). We want b by itself, to do that we get rid of the sqrt(2). By dividing both sides of the equation by sqrt(2) it leaves b= 6/(sqrt(2))

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

zpupster
  • zpupster
b= 6/(sqrt(2)) so plug it in the 2nd equation 3a = 6/(sqrt(2)) divide both sides by 3, now you have a
tayaiv
  • tayaiv
Oh, got it! Thank you :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.