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anonymous
 one year ago
Use absolute value to express the distance between −12 and −15 on the number line.
−12 − (−15) = −27
−12 − (−15) = −3
−12 − (−15) = 3
−12 − (−15) = 27
anonymous
 one year ago
Use absolute value to express the distance between −12 and −15 on the number line. −12 − (−15) = −27 −12 − (−15) = −3 −12 − (−15) = 3 −12 − (−15) = 27

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.02.33  ( 10.166) = 8.33 = 8 1/3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and normal, positive 8 and 1/3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0darn.. thats not one of the answers,

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Negative twelve and onehalf Twelve and onehalf Seven and fivesixths Negative seven and fivesixths

anonymous
 one year ago
Best ResponseYou've already chosen the best response.012 1/2 12 1/2 7 5/6 7 5/6

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0...wow...uh...I really don know...
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