anonymous
  • anonymous
I don't know how to approach this question, please help! Find the value of the constant c for which the line y=4x+c is a tangent to the curve y^2=4x
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
This is what I tried but it doesn't seem to be going anywhere.
rock_mit182
  • rock_mit182
@ganeshie8 help us out
ganeshie8
  • ganeshie8
so far so good

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

ganeshie8
  • ganeshie8
\(16x^2-4x =-8xc-c^2 \) rearrange the equation in standard form \(16x^2+x(8c-4) + c^2 = 0\) For the line to be a tangent, you want the discriminant to be \(0\) : \((8c-4)^2 - 4*16*c^2=0\) solve \(c\)
anonymous
  • anonymous
I am a bit confused with how you rearranged it.
anonymous
  • anonymous
How did you decide to put those numbers in the brackets?
ganeshie8
  • ganeshie8
I wanted to see a quadratic in \(x\), so arranged it in decreasing exponent of \(x\)
ganeshie8
  • ganeshie8
Notice that the equation is in form \(ax^2+bx+c=0\)
anonymous
  • anonymous
Ok, I think I understand better now. So if I started working on it from that last line I would be going in the right direction with it?
ganeshie8
  • ganeshie8
Yes
anonymous
  • anonymous
Thank you!
ganeshie8
  • ganeshie8
yw

Looking for something else?

Not the answer you are looking for? Search for more explanations.