gabbyalicorn
  • gabbyalicorn
Which value of b solves the equation?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
gabbyalicorn
  • gabbyalicorn
gabbyalicorn
  • gabbyalicorn
I'm sorry! I don't want to be a burden on you but, @Luigi0210 could you help me with some more problems, please? :3
Luigi0210
  • Luigi0210
Oh, that should be simple. Do you know what to do when you encounter a negative exponent?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

gabbyalicorn
  • gabbyalicorn
Kind of....
Luigi0210
  • Luigi0210
The rule says, when you have a negative exponent you are allowed to flip it to make it positive. Sound familiar?
gabbyalicorn
  • gabbyalicorn
I thought thats only with -5-(-5) ? They cancel out.
Luigi0210
  • Luigi0210
That's a different rule (: But what I mean, is, let's say you have something like \(\Large 5^{-2} \), you are allowed to flip it so that negative 2 is positive again, like so: \(\huge \frac{1}{5^2} \) And the opposite can be done as well
gabbyalicorn
  • gabbyalicorn
Oh, that...I've seen that before...
gabbyalicorn
  • gabbyalicorn
But I don't get the B part, tho.
Luigi0210
  • Luigi0210
B is just a variable, like x, that you have to solve, so let's solve it: So let's flip everything to make that exponent positive \(\Large \frac{1}{b^3} = 216 \) Now, let's get rid of that cube: \(\Large (\frac{1}{b^3})^{1/3}=(216)^{1/3}\) Which leaves us with \(\Large \frac{1}{b} = 6\) make sense so far?
gabbyalicorn
  • gabbyalicorn
Somewhat.
Luigi0210
  • Luigi0210
What are you confused on?
gabbyalicorn
  • gabbyalicorn
What's the 1/3 suppose to represent? The exponent. If it is. did u do anything to the 216? (like subtract or divide)
Luigi0210
  • Luigi0210
Wait, I think I made an error, I wasn't suppose to flip that 1/216. Sorry, it'll just be \(\Large \frac{1}{b}=\frac{1}{216} \) And yes, that 1/3 is considered an exponent in this certain problem. The 216, I took the cubic root of it along with the 1/b^3
gabbyalicorn
  • gabbyalicorn
Okay.
Luigi0210
  • Luigi0210
\(\Large \frac{1}{b^3} =\frac{1}{216} \) \(\Large (\frac{1}{b^3} )^{1/3} = (\frac{1}{216})^{1/3}\) \(\Large \frac{1}{b} =\frac{1}{6} \) Now flip them: \(\Large b=6 \) Which, if you plug it in, would make the statement true
Luigi0210
  • Luigi0210
Sorry if I went a bit quick >><
gabbyalicorn
  • gabbyalicorn
No worries! :) Is the problem asking what number (b) equals to 216
Luigi0210
  • Luigi0210
Yes, which is the same as 1/216, which would be 6 with that negative exponent.
gabbyalicorn
  • gabbyalicorn
but couldn't we just do 216 รท 2 and then we will find out what b equals
Luigi0210
  • Luigi0210
216/2? That's 108?
gabbyalicorn
  • gabbyalicorn
yes, it is.
Luigi0210
  • Luigi0210
How is that 6? o.O
gabbyalicorn
  • gabbyalicorn
oh, b is suppose to equal to 6?
Luigi0210
  • Luigi0210
Yea, 6^3=216, and 6^{-3} = 1/216
gabbyalicorn
  • gabbyalicorn
oooooooooooh! The answer is 6!
Luigi0210
  • Luigi0210
Yea, I even showed you how to solve it <,<
gabbyalicorn
  • gabbyalicorn
:o ^///^ sorry! I just started to get it cX
gabbyalicorn
  • gabbyalicorn
Thank you.

Looking for something else?

Not the answer you are looking for? Search for more explanations.