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anonymous

  • one year ago

The actual density of iron is 7.874 g/mL. In a laboratory investigation, Jason finds the density of a piece of iron to be 7.921 g/mL. What is the percent error that is associated with Jason’s measurement? -4.7% -0.6% 0.6% 4.7%

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  1. RamiroCruzo
    • one year ago
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    "Percentage Error": show the error as a percent of the exact value ... so divide by the exact value and make it a percentage: \[\frac{ 7.921-7.874 }{ 7.874 }\times100=0.59\approx0.6 %\]

  2. anonymous
    • one year ago
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    Thank you!

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