New school year I forgot how to Algebra! Help me to remember!!
A ball is thrown into the air with an upward velocity of 28 ft/s. Its height (h) in feet after t seconds is given by the function h = -16t^2 + 28t + 7. How long does it take the ball to reach its maximum height? What is the ball’s maximum height? Round to the nearest hundredth, if necessary.
Stacey Warren - Expert brainly.com
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Don't give me the answer! TEACH ME!
Are you famiilar with finding the derivative of a function?
No, if that's how you solve this, I might remember.
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ok well you can solve it by finding the vertex of the parabola . The raph is a parabola with a maximum value which corresponds to maximum height of the ball
excuse the drawing
Its fine. So do I just fined the coordinates of the tip top of the hill?
yea - I'm a bit rusty at this myself I normally would use calculus but lets try it:-
convert the formula to vertex form
h = - 16t^2 + 28t - 7
= 16(t^2 + 1.75t) - 7
= -16(( t + 0.875)^2 - 0.765625)) - 7
which gives t = 0.875 seconds and vertex = -16*-0.765625 + 7 = 19.25 feet
I completed the square on t^2 - 1.75t
Ok, you kinda gave me the answer but ill use what you have as a example template
thers some typos ther
do you want them corrected?
The more I go over these problems the more ill remember, sadly everything is still blank XD
h = - 16t^2 + 28t + 7
= 16(t^2 - 1.75t) + 7
= -16(( t - 0.875)^2 - 0.765625)) + 7
this gives the time t = 0.875 seconds and the maximum height
= -16 * -0.765625 + 7 = 19.25 ft