anonymous
  • anonymous
how would i state the domain for this: f(x) = - 2 cot 3x
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
is that a 3x or cot^3 (x)
anonymous
  • anonymous
3x
rock_mit182
  • rock_mit182
let's say U = 3x. Y = -2 cot (U). Do you remember the identity of cot (U) =

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rock_mit182
  • rock_mit182
?
rock_mit182
  • rock_mit182
@kirarittgers
anonymous
  • anonymous
no i dont know what that means
rock_mit182
  • rock_mit182
cot (U) = \[\frac{ \cos (u) }{ \sin(u) }\]
anonymous
  • anonymous
oh yeah i knew that
anonymous
  • anonymous
but what do i do with that
rock_mit182
  • rock_mit182
;) now, to find out your domain we have to avoid \[\frac{ 0 }{ 0 }\]
rock_mit182
  • rock_mit182
cause \[\frac{ 0 }{ 0 }\] doesn't make sense in math is jut not allowed
anonymous
  • anonymous
no shh i really knew that i just didnt know what you were asking and i still know that what i dont understan is how to state it
rock_mit182
  • rock_mit182
so we need to avoid those values tha makes: \[\frac{ \cos u }{ \sin u }\]
anonymous
  • anonymous
he gave you the identity, now he's trying to avoid sin U where sin U = 0 so that the function is undefined
rock_mit182
  • rock_mit182
0 over o
anonymous
  • anonymous
like i know it cant equal pi/3 or any other vertical asymtope but i dont know how to write that
anonymous
  • anonymous
i know the values it cant equal though i need to know how to write it
rock_mit182
  • rock_mit182
well it is getting harder to explain LOL
rock_mit182
  • rock_mit182
Do you have how to graph that function ?
anonymous
  • anonymous
how bout you just tell me the answer lol because i already know everything i dont need explaining i need to know how its supposed to be writen
anonymous
  • anonymous
yes i do
anonymous
  • anonymous
ive already graphed it
anonymous
  • anonymous
do you understand what im asking like you know how you write it in parenthesis i need to know how im supposed to put the values in there
rock_mit182
  • rock_mit182
of course i do , but what i cannot do, here, is just give ramdom answers
anonymous
  • anonymous
its not random but oh well

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