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is3535

  • one year ago

help

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  1. is3535
    • one year ago
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    @phi @partyqueen

  2. is3535
    • one year ago
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    @paki

  3. is3535
    • one year ago
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    |dw:1441998613082:dw|

  4. is3535
    • one year ago
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    @pinklion23

  5. Nnesha
    • one year ago
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    when we multiply same bases we should `add` exponents \[\huge\rm x^m \times x^n=x^{m+n}\] and when we divide same base , `subtract` their exponents \[\huge\rm \frac{ x^m }{ x^n }=x^{m-n}\]

  6. Nnesha
    • one year ago
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    so \[7^{-3} \times 7^{9}=?\]

  7. is3535
    • one year ago
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    |dw:1441998736665:dw|

  8. is3535
    • one year ago
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    7^-14

  9. Nnesha
    • one year ago
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    hmm how did you get *negative * 14

  10. is3535
    • one year ago
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    i just guess

  11. Nnesha
    • one year ago
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    don't guess it's easy when multiply same bases we should `add` their exponents so \[7^{-3} \times 7^{9}=\rm what ?\]

  12. pinklion23
    • one year ago
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    lol

  13. pinklion23
    • one year ago
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    -3+9=9-3

  14. is3535
    • one year ago
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    117649

  15. Nnesha
    • one year ago
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    well don't use calculator

  16. Nnesha
    • one year ago
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    here is an example \[\huge\rm 2^2 \times 2^3 = 2^{2+3} = 2^5\] base would stay the same \[\large\rm 7^{-3} \times 7^9=7^{-3+9}=7^?\]

  17. is3535
    • one year ago
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    2

  18. Nnesha
    • one year ago
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    mind telling how u got 2 ?

  19. is3535
    • one year ago
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    there 2 number 3 and 9

  20. is3535
    • one year ago
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    it so hard

  21. Nnesha
    • one year ago
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    i said just `add` exponents -3 and 9 are exponents 9-3= ??

  22. is3535
    • one year ago
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    9-3 = 6

  23. Nnesha
    • one year ago
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    yes right so numerator would be 7^6 \[\huge\rm \frac{ 7^6 }{ 7^{-8} }\] 2nd exponent rule when we divide same base we should `subtract` their exponents here is an example \[\huge\rm \frac{ 2^4 }{ 2^{-3} }=2^{4-(-3)}\]

  24. is3535
    • one year ago
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    2^4-(-3) you add

  25. Nnesha
    • one year ago
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    we would bec 2nd exponent is negative that would makes addition

  26. is3535
    • one year ago
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    4^2

  27. Nnesha
    • one year ago
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    what is 4^2 ?

  28. is3535
    • one year ago
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    |dw:1441999674369:dw|

  29. Nnesha
    • one year ago
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    here is an example \[\huge\rm \frac{ 2^4 }{ 2^{-3} }=2^{4-(-3)}=2^{4+3}=2^7\] basically we are subtracting 4 from -3 4-(-3) but bec 3 is negative that would makes positive 3

  30. Nnesha
    • one year ago
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    what about 4^2 ? \[\huge\rm \frac{ 7^6 }{ 7^{-8} } = ?\]

  31. is3535
    • one year ago
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    i think it A OR B

  32. Nnesha
    • one year ago
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    i have no idea what A or B ...

  33. is3535
    • one year ago
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    |dw:1441999981329:dw|

  34. Nnesha
    • one year ago
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    look at the example then solve this \[\huge\rm \frac{ 7^6 }{ 7^{-8} } = ?\]

  35. is3535
    • one year ago
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    ok

  36. Nnesha
    • one year ago
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    here is an example \[\huge\rm \frac{ 2^4 }{ 2^{-3} }=2^{4-(-3)}=2^{4+3}=2^7\] in this example base is 2

  37. is3535
    • one year ago
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    i said 2^7

  38. Nnesha
    • one year ago
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    you never said that anyways that's an example now solve ur question which is \[\huge\rm \frac{ 7^6 }{ 7^{-8} } = ?\]

  39. Nnesha
    • one year ago
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    move the exponent from denominator to top when you do that sign of the denominator exponent would change

  40. is3535
    • one year ago
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    ok ty

  41. is3535
    • one year ago
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    it was worng

  42. Nnesha
    • one year ago
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    which one ?

  43. Nnesha
    • one year ago
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    what did you get ?

  44. Nnesha
    • one year ago
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    i didn't give you the answer you didn't tell me which one you get

  45. is3535
    • one year ago
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    it was 7^14

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