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anonymous
 one year ago
I only have two questions left in my homework that's due tonight before midnight and I need help with them.
Prove the statement using the ε, δ definition of a limit.
lim x^2 = 0
x→0
Given ε > 0, we need δ > 0 such that if 0 < x − 0 < δ, then x^2 − 0 < ε ⇔ (blank) < ε ⇔ x< (blank). Take δ = (blank). Then 0 < x − 0 < δ right double arrow implies x^2 − 0 < ε. Thus, lim x^2 = 0 by the definition of a limit.
x→0
Use the given graph of f to find a number δ such that if
x − 1 < δ then f(x) − 1 < 0.2 δ = (Blank)
Graph:
http://www.webassign.net/scalcet7/24001.gif
anonymous
 one year ago
I only have two questions left in my homework that's due tonight before midnight and I need help with them. Prove the statement using the ε, δ definition of a limit. lim x^2 = 0 x→0 Given ε > 0, we need δ > 0 such that if 0 < x − 0 < δ, then x^2 − 0 < ε ⇔ (blank) < ε ⇔ x< (blank). Take δ = (blank). Then 0 < x − 0 < δ right double arrow implies x^2 − 0 < ε. Thus, lim x^2 = 0 by the definition of a limit. x→0 Use the given graph of f to find a number δ such that if x − 1 < δ then f(x) − 1 < 0.2 δ = (Blank) Graph: http://www.webassign.net/scalcet7/24001.gif

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IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0dw:1442003910517:dw
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