anonymous
  • anonymous
What is the missing exponent? (12^-5)^2 l_____l ----------=12 12^-4
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
anonymous
  • anonymous
help
Nnesha
  • Nnesha
you need to know 2 exponent rules \[\huge\rm (x^m)^n=x^{m \times n}\] and the 2nd one \[\huge\rm \frac{ x^m }{ x^n }=x^{m-n}\]when we divide same bases we should subtract their exponents

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Nnesha
  • Nnesha
so \[\huge\rm (12^{-5})^2 = ?\]
anonymous
  • anonymous
61917364224
Nnesha
  • Nnesha
use the exponent rule i gave you don't use calculator .
Nnesha
  • Nnesha
so \[\huge\rm (12^{-5})^2 = ?\] \[\huge\rm (x^m)^n=x^{m \times n}\]multiply the exponents
anonymous
  • anonymous
20^?
anonymous
  • anonymous
i mean 12^?
Nnesha
  • Nnesha
what are the exponents \[\huge\rm (12^{-5})^2 = ?\] ?
anonymous
  • anonymous
|dw:1441998729441:dw|
Nnesha
  • Nnesha
example \[\huge\rm (2^3)^4=2^{3 \times 4}=2^{12}\]
anonymous
  • anonymous
so 12 ^2
Nnesha
  • Nnesha
let's solve the numerator first , look at the example i gave you \[\huge\rm (12^{-5})^2 = ?\]
Nnesha
  • Nnesha
multiply the 2 with the exponent of -12
anonymous
  • anonymous
24
anonymous
  • anonymous
144
Nnesha
  • Nnesha
\[\huge\rm (12^{-5})^2 = 12^{-5 \times 2}= 12^{??}\]

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