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anonymous

  • one year ago

What is the missing exponent? 8^-5/(8^-7)^2=8[ ]

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  1. anonymous
    • one year ago
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    @Nnesha help again please?

  2. Nnesha
    • one year ago
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    you need to know 2 exponent rules \[\huge\rm (x^m)^n=x^{m \times n}\] and the 2nd one \[\huge\rm \frac{ x^m }{ x^n }=x^{m-n}\]when we divide same bases we should subtract their exponents

  3. anonymous
    • one year ago
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    so for the first one it's -7 times 2 the second one is -5 times -7? @nnesha

  4. Nnesha
    • one year ago
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    first one is right 2nd one you should `subtract` their exponent not multiply them

  5. Nnesha
    • one year ago
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    \[\frac{ 8^{-5} }{ 8^{-7 \times 2} }\] -7 times 2 = ?

  6. anonymous
    • one year ago
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    -14?

  7. Nnesha
    • one year ago
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    yes right so \[\frac{ 8^{-5} }{ 8^{-14}}\]

  8. Nnesha
    • one year ago
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    now apply 2nd exponent rule

  9. anonymous
    • one year ago
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    is it -11? I might be wrong

  10. Nnesha
    • one year ago
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    here is an example \[\huge\rm \frac{ 2^3 }{ 2^{-3} } =2^{3\color{ReD}{-}(-3)}\]

  11. Nnesha
    • one year ago
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    we should subtract their exponents but if the exponents at the denominator is negative then you should add \[\huge\rm \frac{ 2^3 }{ 2^{-3} } =2^{3\color{ReD}{-}(-3)} =2^{3+3}\]

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