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anonymous
 one year ago
What is the missing exponent? 8^5/(8^7)^2=8[ ]
anonymous
 one year ago
What is the missing exponent? 8^5/(8^7)^2=8[ ]

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Nnesha help again please?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0you need to know 2 exponent rules \[\huge\rm (x^m)^n=x^{m \times n}\] and the 2nd one \[\huge\rm \frac{ x^m }{ x^n }=x^{mn}\]when we divide same bases we should subtract their exponents

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so for the first one it's 7 times 2 the second one is 5 times 7? @nnesha

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0first one is right 2nd one you should `subtract` their exponent not multiply them

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 8^{5} }{ 8^{7 \times 2} }\] 7 times 2 = ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0yes right so \[\frac{ 8^{5} }{ 8^{14}}\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0now apply 2nd exponent rule

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is it 11? I might be wrong

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0here is an example \[\huge\rm \frac{ 2^3 }{ 2^{3} } =2^{3\color{ReD}{}(3)}\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0we should subtract their exponents but if the exponents at the denominator is negative then you should add \[\huge\rm \frac{ 2^3 }{ 2^{3} } =2^{3\color{ReD}{}(3)} =2^{3+3}\]
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