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  1. Spring98
    • one year ago
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    @Hero

  2. Spring98
    • one year ago
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    @Loser66

  3. Spring98
    • one year ago
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    can you help me plz?

  4. anonymous
    • one year ago
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    When powers with the same base are multiplied, the base is unchanged and the exponents are added together. Example\[5^3 \times 5^2 = 5^{3+2} = 5^5\]When powers with the same base are divided, the base is unchanged and the exponents are subtracted. Example\[\frac{ 7^4 }{ 7^2 } = 7^{4-2} = 7^2\]

  5. Spring98
    • one year ago
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    https://cv-kettle-falls.brainhoney.com/Resource/30603643,0/Assets/75122_53df8565/01_08_22b.gif so is this the answer to my question?

  6. anonymous
    • one year ago
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    No.

  7. Spring98
    • one year ago
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    so would it be this ? https://cv-kettle-falls.brainhoney.com/Resource/30603643,0/Assets/75122_53df8565/01_08_22d.gif

  8. anonymous
    • one year ago
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    There's no need to guess. I've given you all the information required for you to solve the problem. Try it.

  9. Spring98
    • one year ago
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    im asking you the ones i think it is are they any of the ones that i asked u?

  10. anonymous
    • one year ago
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    Please show me how you got your answers. I'm here to help.

  11. Spring98
    • one year ago
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    @KAKES1967 @Luigi0210 @Nnesha @iGreen

  12. Spring98
    • one year ago
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    @i

  13. Spring98
    • one year ago
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    @icecreamman

  14. jdoe0001
    • one year ago
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    what would say.... \(\bf \large 4^4\cdot 4^3\) be?

  15. Spring98
    • one year ago
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    4^7

  16. jdoe0001
    • one year ago
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    yeap, thus \(\bf \cfrac{4^4\cdot 4^3}{4^5}\implies \cfrac{4^7}{4^5} \\ \quad \\ a^{-{\color{red} n}} \implies \cfrac{1}{a^{\color{red} n}}\qquad \qquad \cfrac{1}{a^{\color{red} n}}\implies a^{-{\color{red} n}}\qquad thus \\ \quad \\ \cfrac{4^7}{4^5}\implies \cfrac{4^7}{1}\cdot \cfrac{1}{4^5}\implies 4^7\cdot 4^{{\color{red}{ -5}}}\implies 4^{7-5}\implies 4^2\)

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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