anonymous
  • anonymous
What is the quotient: (3x^3 + 14x^2 + 13x - 6) / (3x - 1) ?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
AbdullahM
  • AbdullahM
Do you know group factoring?
anonymous
  • anonymous
No
AbdullahM
  • AbdullahM
Group factoring is like: \[x^3 + x^2 + x + 1 = x^2(x+1) + 1(x+1) = (x+1)(x^2+1)\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
I don't really remember learning about that, but I think I understand a little bit
AbdullahM
  • AbdullahM
so you need to group factor the numerator
AbdullahM
  • AbdullahM
oh, wait. It can't be group factored >.<
AbdullahM
  • AbdullahM
The Rational Root Theorem tells you that if the polynomial has a rational zero then it must be a fraction p/q, where p is a factor of the trailing constant and q is a factor of the leading coefficient. and so using that, these could be possible roots \[\pm \frac{ 1 }{ 1 } , ~ \pm \frac{ 1 }{ 3 } , ~ \pm \frac{ 2 }{ 1 } , ~ \pm \frac{ 2 }{ 3 } , ~ \pm \frac{ 3 }{ 1 } , ~ \pm \frac{ 3 }{ 3 } , ~ \pm \frac{ 6 }{ 1 } , ~ \pm \frac{ 6 }{ 3 } ~\]
AbdullahM
  • AbdullahM
solve 3x-1 = 0 x = 1/3 and since that is one of the possible roots, we can use that since it might be divisible by it.
AbdullahM
  • AbdullahM
can someone explain? ;-; this is hard to show online compared to in-person with a piece of paper ;-;
AbdullahM
  • AbdullahM
someone else*
Nnesha
  • Nnesha
long division
AbdullahM
  • AbdullahM
ik, but latex isn't that easy to use to show that ;-; and the draw tool isn't that easy either ;-;
Nnesha
  • Nnesha
for long division 5 steps) \(\huge\color{green}{{1:}}\) Divide the first terms \(\huge\color{green}{{2:}}\) multiply(distribute) \(\huge\color{green}{{3:}}\) subtract all terms \(\huge\color{green}{{4:}}\) carry down \(\huge\color{green}{{5:}}\) repeat
Nnesha
  • Nnesha
haha true that !
Nnesha
  • Nnesha
|dw:1442023891316:dw| divide first terms \[\huge\rm \frac{ 3x^3 }{ 3x } = ???\] then multiply the divisor with that
Nnesha
  • Nnesha
^ divide first term of polynomial by first term of the divisor
Nnesha
  • Nnesha
wait for `ookay` :=)
AbdullahM
  • AbdullahM
thanks :)
Nnesha
  • Nnesha
yw :=)

Looking for something else?

Not the answer you are looking for? Search for more explanations.