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  1. anonymous
    • one year ago
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    Ok this one is more tricky that the ab one, you know Pythagoras theorem right?

  2. swaugh
    • one year ago
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    i know it its just really confusing to me

  3. anonymous
    • one year ago
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    Ok

  4. anonymous
    • one year ago
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    Basically that line isn't just purely up or down it's diagonal, that means that it has both an x and y component.

  5. anonymous
    • one year ago
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    You can think of the line itself as a hypotenuse and the x and y components as different sides of a right angle triangle, ill draw a picture.

  6. anonymous
    • one year ago
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    |dw:1442021866088:dw|

  7. anonymous
    • one year ago
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    Therefore the length of the line H is: x^2 + y^2 = H^2

  8. anonymous
    • one year ago
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    You try solve it from there ok

  9. swaugh
    • one year ago
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    is it 6

  10. anonymous
    • one year ago
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    Close but not right, can you show me your working?

  11. swaugh
    • one year ago
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    is it 4. when you count the boxes that the line is in you get 4

  12. anonymous
    • one year ago
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    The x component is 3, the y component 4. You have to square both of those and then take the sqrt of the answer you get.

  13. anonymous
    • one year ago
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    Square both of those then add together then sqrt*

  14. swaugh
    • one year ago
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    its 6. 3^2 + 4^2 =25; 25/4 =6.25

  15. anonymous
    • one year ago
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    You did everything right until the last part. Yes you get H^2 = 25 but H = sqrt 25 = 5

  16. swaugh
    • one year ago
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    ohh thank you

  17. anonymous
    • one year ago
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    Np, im glad to help ;)

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