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Ok this one is more tricky that the ab one, you know Pythagoras theorem right?
i know it its just really confusing to me
Basically that line isn't just purely up or down it's diagonal, that means that it has both an x and y component.
You can think of the line itself as a hypotenuse and the x and y components as different sides of a right angle triangle, ill draw a picture.
Therefore the length of the line H is: x^2 + y^2 = H^2
You try solve it from there ok
is it 6
Close but not right, can you show me your working?
is it 4. when you count the boxes that the line is in you get 4
The x component is 3, the y component 4. You have to square both of those and then take the sqrt of the answer you get.
Square both of those then add together then sqrt*
its 6. 3^2 + 4^2 =25; 25/4 =6.25
You did everything right until the last part. Yes you get H^2 = 25 but H = sqrt 25 = 5
ohh thank you
Np, im glad to help ;)