## vera_ewing one year ago Evaluate

1. Hero

Replace x with n-5 On both sides of the equation

2. Hero

Then simplify the right side.

3. Hero

Until you get to the correct result From the given choices.

4. Hero

Show me how you got that result.

5. Hero

6. Hero

You know I'm going to ask you to show your work to See if you really did the work .

7. zepdrix

$\large\rm g(\color{orangered}{x})=\frac{(\color{orangered}{x})^2-6}{2(\color{orangered}{x})}$Woops! You didn't put the -5 in the correct place!$\large\rm g(\color{orangered}{n-5})=\frac{(\color{orangered}{n-5})^2-6}{2(\color{orangered}{n-5})}$You're replacing all the oranges with the new oranges :d

8. Nnesha

(n-5)^2 isn't n^2 +25 (n-5)^2 is same as (n-5)(n-5) use foil method yo should get 3 terms

9. Nnesha

|dw:1442026794010:dw| multiply the top with left term

10. Nnesha

(n-5)(n-5) = n^2 -10n +19 ???

11. Here_to_Help15

g(x) = (x^2-6)/(2x) g(n-5) = [(n-5)^2 - 6]/[2(n-5)] = (n^2 - 10n + 25 - 6)/(2n - 10) = (n^2-10n + 19)/(2n-10) Always remember the "x" in the function definition g(x) is a dummy variable that is nothing more than a placeholder for whatever value you want to use to evaluate the function. Replace the "x" with whatever you want to use for evaluating the function: g(x) = (x^2-6)/(2x) g(a) = (a^2-6)/(2x) g(coconut) = (coconut^2 - 6)/(2*coconut) g(red & yellow sunset) = [(red & yellow sunset)^2 - 6]/[2*(red ^ yellow sunset)] g(n-5) = [(n-5)^2 - 6]/[2*(n-5)]

12. Nnesha

no that's not right thats a guess..

13. Here_to_Help15

Another tip is to plug n-5 for x

14. Nnesha

|dw:1442027083713:dw| distribute n (n-5) and then -5(n-5) write ur answer in the box

15. Nnesha

example $\large\rm a(b+c)=a \times b +a \times c =ab +ac$

16. Nnesha

perfect ! combine like terms

17. zepdrix

ya c:

18. zepdrix

$\large\rm g(n-5)=\frac{\color{royalblue}{(n-5)^2}-6}{2(n-5)}$ So you expanded out your square in the numerator:$\large\rm g(n-5)=\frac{\color{royalblue}{n^2-10n+25}-6}{2(n-5)}$Gotta take it a little bit further :)

19. zepdrix

So what is your denominator going to look like? $$\large\rm 2(n-5)=?$$ Hmmm

20. zepdrix

yay good job \c:/

21. Nnesha

saworry