vera_ewing
  • vera_ewing
Evaluate
Mathematics
katieb
  • katieb
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Hero
  • Hero
Replace x with n-5 On both sides of the equation
Hero
  • Hero
Then simplify the right side.
Hero
  • Hero
Until you get to the correct result From the given choices.

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Hero
  • Hero
Show me how you got that result.
Hero
  • Hero
@Vera_Ewing post your steps.
Hero
  • Hero
You know I'm going to ask you to show your work to See if you really did the work .
zepdrix
  • zepdrix
\[\large\rm g(\color{orangered}{x})=\frac{(\color{orangered}{x})^2-6}{2(\color{orangered}{x})}\]Woops! You didn't put the -5 in the correct place!\[\large\rm g(\color{orangered}{n-5})=\frac{(\color{orangered}{n-5})^2-6}{2(\color{orangered}{n-5})}\]You're replacing all the oranges with the new oranges :d
Nnesha
  • Nnesha
(n-5)^2 isn't n^2 +25 (n-5)^2 is same as (n-5)(n-5) use foil method yo should get 3 terms
Nnesha
  • Nnesha
|dw:1442026794010:dw| multiply the top with left term
Nnesha
  • Nnesha
(n-5)(n-5) = n^2 -10n +19 ???
Here_to_Help15
  • Here_to_Help15
g(x) = (x^2-6)/(2x) g(n-5) = [(n-5)^2 - 6]/[2(n-5)] = (n^2 - 10n + 25 - 6)/(2n - 10) = (n^2-10n + 19)/(2n-10) Always remember the "x" in the function definition g(x) is a dummy variable that is nothing more than a placeholder for whatever value you want to use to evaluate the function. Replace the "x" with whatever you want to use for evaluating the function: g(x) = (x^2-6)/(2x) g(a) = (a^2-6)/(2x) g(coconut) = (coconut^2 - 6)/(2*coconut) g(red & yellow sunset) = [(red & yellow sunset)^2 - 6]/[2*(red ^ yellow sunset)] g(n-5) = [(n-5)^2 - 6]/[2*(n-5)]
Nnesha
  • Nnesha
no that's not right thats a guess..
Here_to_Help15
  • Here_to_Help15
Another tip is to plug n-5 for x
Nnesha
  • Nnesha
|dw:1442027083713:dw| distribute n (n-5) and then -5(n-5) write ur answer in the box
Nnesha
  • Nnesha
example \[\large\rm a(b+c)=a \times b +a \times c =ab +ac \]
Nnesha
  • Nnesha
perfect ! combine like terms
zepdrix
  • zepdrix
ya c:
zepdrix
  • zepdrix
\[\large\rm g(n-5)=\frac{\color{royalblue}{(n-5)^2}-6}{2(n-5)}\] So you expanded out your square in the numerator:\[\large\rm g(n-5)=\frac{\color{royalblue}{n^2-10n+25}-6}{2(n-5)}\]Gotta take it a little bit further :)
zepdrix
  • zepdrix
So what is your denominator going to look like? \(\large\rm 2(n-5)=?\) Hmmm
zepdrix
  • zepdrix
yay good job \c:/
Nnesha
  • Nnesha
saworry

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