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vera_ewing

  • one year ago

Evaluate

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  1. Hero
    • one year ago
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    Replace x with n-5 On both sides of the equation

  2. Hero
    • one year ago
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    Then simplify the right side.

  3. Hero
    • one year ago
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    Until you get to the correct result From the given choices.

  4. Hero
    • one year ago
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    Show me how you got that result.

  5. Hero
    • one year ago
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    @Vera_Ewing post your steps.

  6. Hero
    • one year ago
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    You know I'm going to ask you to show your work to See if you really did the work .

  7. zepdrix
    • one year ago
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    \[\large\rm g(\color{orangered}{x})=\frac{(\color{orangered}{x})^2-6}{2(\color{orangered}{x})}\]Woops! You didn't put the -5 in the correct place!\[\large\rm g(\color{orangered}{n-5})=\frac{(\color{orangered}{n-5})^2-6}{2(\color{orangered}{n-5})}\]You're replacing all the oranges with the new oranges :d

  8. Nnesha
    • one year ago
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    (n-5)^2 isn't n^2 +25 (n-5)^2 is same as (n-5)(n-5) use foil method yo should get 3 terms

  9. Nnesha
    • one year ago
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    |dw:1442026794010:dw| multiply the top with left term

  10. Nnesha
    • one year ago
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    (n-5)(n-5) = n^2 -10n +19 ???

  11. Here_to_Help15
    • one year ago
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    g(x) = (x^2-6)/(2x) g(n-5) = [(n-5)^2 - 6]/[2(n-5)] = (n^2 - 10n + 25 - 6)/(2n - 10) = (n^2-10n + 19)/(2n-10) Always remember the "x" in the function definition g(x) is a dummy variable that is nothing more than a placeholder for whatever value you want to use to evaluate the function. Replace the "x" with whatever you want to use for evaluating the function: g(x) = (x^2-6)/(2x) g(a) = (a^2-6)/(2x) g(coconut) = (coconut^2 - 6)/(2*coconut) g(red & yellow sunset) = [(red & yellow sunset)^2 - 6]/[2*(red ^ yellow sunset)] g(n-5) = [(n-5)^2 - 6]/[2*(n-5)]

  12. Nnesha
    • one year ago
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    no that's not right thats a guess..

  13. Here_to_Help15
    • one year ago
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    Another tip is to plug n-5 for x

  14. Nnesha
    • one year ago
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    |dw:1442027083713:dw| distribute n (n-5) and then -5(n-5) write ur answer in the box

  15. Nnesha
    • one year ago
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    example \[\large\rm a(b+c)=a \times b +a \times c =ab +ac \]

  16. Nnesha
    • one year ago
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    perfect ! combine like terms

  17. zepdrix
    • one year ago
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    ya c:

  18. zepdrix
    • one year ago
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    \[\large\rm g(n-5)=\frac{\color{royalblue}{(n-5)^2}-6}{2(n-5)}\] So you expanded out your square in the numerator:\[\large\rm g(n-5)=\frac{\color{royalblue}{n^2-10n+25}-6}{2(n-5)}\]Gotta take it a little bit further :)

  19. zepdrix
    • one year ago
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    So what is your denominator going to look like? \(\large\rm 2(n-5)=?\) Hmmm

  20. zepdrix
    • one year ago
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    yay good job \c:/

  21. Nnesha
    • one year ago
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    saworry

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