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anonymous
 one year ago
what is the sample size formula for ME=2√(P(1P)/n) if ME= margin errors, P= percentage of people responding in a certain way, and n is the size of the sample?
anonymous
 one year ago
what is the sample size formula for ME=2√(P(1P)/n) if ME= margin errors, P= percentage of people responding in a certain way, and n is the size of the sample?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I need it to solve a problem......is it like this? n= (p(1p)*2^2)/(ME^2)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Is the given formula\[ME=2 \sqrt{\frac{ P(1P) }{ n }}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry, I was answering the other problems

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0And is your answer\[n=\frac{ 4P(1P) }{ ME^2 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well, I did it like this n= (p(1p)*2^2)/(ME^2 )

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Right, but I'm having a hard time deciphering the brackets. Knowing that \(2^2=4\), is my last post the same as your answer?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh, jaja you are right. Didn't noticed that XD

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well then, you are correct! Well done!
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