## anonymous one year ago what is the sample size formula for ME=2√(P(1-P)/n) if ME= margin errors, P= percentage of people responding in a certain way, and n is the size of the sample?

1. anonymous

I need it to solve a problem......is it like this? n= (p(1-p)*2^2)/(ME^2)

2. anonymous

Is the given formula$ME=2 \sqrt{\frac{ P(1-P) }{ n }}$

3. anonymous

Hello?

4. anonymous

yes

5. anonymous

sorry, I was answering the other problems

6. anonymous

And is your answer$n=\frac{ 4P(1-P) }{ ME^2 }$

7. anonymous

well, I did it like this n= (p(1-p)*2^2)/(ME^2 )

8. anonymous

Right, but I'm having a hard time deciphering the brackets. Knowing that $$2^2=4$$, is my last post the same as your answer?

9. anonymous

oh, jaja you are right. Didn't noticed that XD

10. anonymous

Well then, you are correct! Well done!

11. anonymous

thank you

12. anonymous

You're welcome