anonymous
  • anonymous
what is the sample size formula for ME=2√(P(1-P)/n) if ME= margin errors, P= percentage of people responding in a certain way, and n is the size of the sample?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
I need it to solve a problem......is it like this? n= (p(1-p)*2^2)/(ME^2)
anonymous
  • anonymous
Is the given formula\[ME=2 \sqrt{\frac{ P(1-P) }{ n }}\]
anonymous
  • anonymous
Hello?

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anonymous
  • anonymous
yes
anonymous
  • anonymous
sorry, I was answering the other problems
anonymous
  • anonymous
And is your answer\[n=\frac{ 4P(1-P) }{ ME^2 }\]
anonymous
  • anonymous
well, I did it like this n= (p(1-p)*2^2)/(ME^2 )
anonymous
  • anonymous
Right, but I'm having a hard time deciphering the brackets. Knowing that \(2^2=4\), is my last post the same as your answer?
anonymous
  • anonymous
oh, jaja you are right. Didn't noticed that XD
anonymous
  • anonymous
Well then, you are correct! Well done!
anonymous
  • anonymous
thank you
anonymous
  • anonymous
You're welcome

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