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Anguyennn
 one year ago
Could someone please help me simplify 32(3x4)(3x+4)(x+2)(2x1)?
Anguyennn
 one year ago
Could someone please help me simplify 32(3x4)(3x+4)(x+2)(2x1)?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do you know the foil rule for expanding brackets?

Anguyennn
 one year ago
Best ResponseYou've already chosen the best response.0yes so I got 32(9x^2+12x12x+16)(2x^2x+4x2) is that correct?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yep thats right, now just times the number outside the brackets by everything inside.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Simplify the inside of the brackets firstb to make it easier

Anguyennn
 one year ago
Best ResponseYou've already chosen the best response.0do you minus 32 first? .....so it would be 1(9x^2+12x12x+16)(2x^2x+4x2)?

Anguyennn
 one year ago
Best ResponseYou've already chosen the best response.0(9x^2+16)(2x^2+3x2)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No you can't do that, the 2 is multiplies by brackets its a different type of term than the 3 by itslef, so you cant add them

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah what you did was right

Anguyennn
 one year ago
Best ResponseYou've already chosen the best response.0ok now do I multiply the first bracket with 2?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but remeber only add things if they have the same thing, for example x^3 and x^2 cant add together, but x^2 and 2x^2 can add to 3x^3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0onceyou multiply the bracket by 2 you can start combining like terms (same power of x)

Anguyennn
 one year ago
Best ResponseYou've already chosen the best response.0but what about the 3?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0leave that to last, you can only combine it with other numbers by itself (not multiplied by an x)

Anguyennn
 one year ago
Best ResponseYou've already chosen the best response.0so right now I am getting 3(18x^2+32)(2x^2x+4x2)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0just leave the 3, and you forgot about the x in the first bracket

Anguyennn
 one year ago
Best ResponseYou've already chosen the best response.0but it cancels out doesn't it? because 12x12x is 0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh yeah true that i forgot :P

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So you have 32(9x^2+12x12x+16)(2x^2x+4x2) this becomes 3 2(9x^2 + 16) (2x^2+3x2) this becomes 3 (18x^232) 2x^23x+2 this becomes 3 18x^2 + 32 2x^2 3x +2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Now combine like terms

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0on the last line (i screwed up a couple of lines up)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0of i see what was wrong

Anguyennn
 one year ago
Best ResponseYou've already chosen the best response.0because at the beginning its (3x4)(3x+4)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i accidentaly put +16 when it was 16

Anguyennn
 one year ago
Best ResponseYou've already chosen the best response.0and when you multiply them together its 16

Anguyennn
 one year ago
Best ResponseYou've already chosen the best response.0multiplied with 2 is 32

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry for the mistake :P

Anguyennn
 one year ago
Best ResponseYou've already chosen the best response.0so would the answer be 20x^2+3x+33

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yep but should the x one be 3x?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0other than that your right, good job

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0in last brackets 4x  x = 3x as theres a negative in front it becomes 3x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0in front of the brackets

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You have (x+2)(2x1) this becomes (2x^2x+4x2) multiplying everyhting by 1 it becomes 2x^2 +x 4x +2 =2x^23x+2

Anguyennn
 one year ago
Best ResponseYou've already chosen the best response.0why did you multiply everything by 1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0when you have brackets and a number outside like a(b+x) , to expand you multiply b and x by a. Outside those brackets theres a , this just means 1*(2x^2x+4x2), therefore everything is multiplied by 1.

Anguyennn
 one year ago
Best ResponseYou've already chosen the best response.0ohhhh ok i get it now

Anguyennn
 one year ago
Best ResponseYou've already chosen the best response.0so the answer would now be 20x^23x+37

Anguyennn
 one year ago
Best ResponseYou've already chosen the best response.0since you are helping me do you mind helping me with one more math question? please and thank you

Anguyennn
 one year ago
Best ResponseYou've already chosen the best response.0so now its factoring polynomial expressions and it asks to factor by finding the greatest common factor. and the expression is 12x^2y^218x^3y+24x^2y

Anguyennn
 one year ago
Best ResponseYou've already chosen the best response.0Thank you for your help

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok now factoring is just the reverse of the expanding thing I showed you. Expanding is when you have a number multiplied against brackets and then bringing it all out into a polynomial. Factoring is when you have a plynomial and you turn it into a brackets multiplied against a number.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You're very welcome btw, im glad to help

Anguyennn
 one year ago
Best ResponseYou've already chosen the best response.0so could you help me go through this question step by step so that i will get a hang of it please

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0First you have to find one number that exist in all 3 terms.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0all the terms have x^2 right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the middle one is just X^2 x X

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0however the highest y power is only 1 two have y^1 and one has y^2

Anguyennn
 one year ago
Best ResponseYou've already chosen the best response.0this middle one is different

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0all the terms have a multiple of 6, 6 x 2 = 12 6 x 3 = 18 6 x 4 = 24

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok those are the common factors, you have to find the highest multiple of every variable (in this case x and y) and the highest multiple of the coefficents

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0This means that we can multiply (x^2)(y)(6) by different things to get all the terms

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Does that make sense?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok you will get it better in the next step.

Anguyennn
 one year ago
Best ResponseYou've already chosen the best response.0where did you get 6 from?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Now that we have the highest common factor, we have to find what these multiply against to get each term.

Anguyennn
 one year ago
Best ResponseYou've already chosen the best response.0oh 6 is the common factor

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The 6 is the highest factor of the coeffeicents of each term, it multiplies to make 12 18 and 24

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok (x^2)(y)(6) * (a+b+c) = the original expression you gave me

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what does (x^2)(y)6 times against to make 12x^2y^2 ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.06(x^2)(y) is the common factor (highest), this means that it can times against a number to make each of the terms

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so the coeffcient must be 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0x^2 x 1 = x^2 , we dont worry about this one

Anguyennn
 one year ago
Best ResponseYou've already chosen the best response.0are you looking at 12x^2y^2 only?

Anguyennn
 one year ago
Best ResponseYou've already chosen the best response.0I am confused to which section of the expression you are explaining to me

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So the number that 6y(x^2) multiplies agasint to make 12x^2y^2 is 2y

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0we are taking each term 1 by 1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0This seems a bit tedious, ill make an easier example so you understand whats going on ok?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok lets say we have ab + ac

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0We want to turn it into a bracket times a number

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the highest common factor in each term is a

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That goes outside the bracket

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Now we find the 2 numbers that a multiplies agasint to make ac and ab

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0these go inside the brackets

Anguyennn
 one year ago
Best ResponseYou've already chosen the best response.0so would it look like 2a(b+c)?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no if you expand it you get a x b + a x c

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0which is ab + ac, what we originally had, this is pretty much what factoring is

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok cool, lets try a harder one then we'll go back to the other

Anguyennn
 one year ago
Best ResponseYou've already chosen the best response.0i am just looking it over

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Remember highest common factor outside brackets, inside goes what it multiplies against to make the orignal terms

Anguyennn
 one year ago
Best ResponseYou've already chosen the best response.0what would the expression look like though?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0a((what a times against to make 2ab) + (what a times against to make a^2))

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0All you're doing is just taking the common factor out leaving everyhting else behind.

Anguyennn
 one year ago
Best ResponseYou've already chosen the best response.0ok so for 12x^2y^2 you are dividing 12 by 6 am i correct?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you also divide by x^2 and y

Anguyennn
 one year ago
Best ResponseYou've already chosen the best response.0and then what is the next step?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Like this (12x^2y^2)/(6(x^2)y)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You get 2y when yo do that

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That is the number which 6(x^2)y times against to make 12x^2y^2 becasue 6(x^2)y * 2y = 12(x^2)(y^)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do the same for the other 2 terms

Anguyennn
 one year ago
Best ResponseYou've already chosen the best response.0where did the squared go for the y?

Anguyennn
 one year ago
Best ResponseYou've already chosen the best response.0isn't it suppose to be 6(x^2y^2) ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(y^2)/y = y when you divide variables you minus the power of the bottom one from the power of the top one (aslong they are the same variable)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0for 12x^2y^2 / 6(x^2)y you split it into 3 parts 12/6 = 2 (x^2)/(x^2) = 1 (y^2)/y = y 2 x 1 x y = 2y

Anguyennn
 one year ago
Best ResponseYou've already chosen the best response.0so how come you didn't do (x^2)/x?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it was (x^2)/(x^2) as (x^2) is the highest common factor

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you divide all 3 terms by 6(x^2)y which is the highest common factor to get the number the highest common factor times agasint to get those terms

Anguyennn
 one year ago
Best ResponseYou've already chosen the best response.0the expression in the middle in x^3 but the other two is x^2 so x^2 is the common factor because there are more of them?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0X^3 is just x*x*x X^2 is x*x, the highest is x*x becasue x*x*x is not a factor of the ones with x*x, its bigger than it. x*x can fit into all of them

Anguyennn
 one year ago
Best ResponseYou've already chosen the best response.0hold on i am looking at the website

Anguyennn
 one year ago
Best ResponseYou've already chosen the best response.0would the whole answer be 2y3x+12

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Just do some practice and you'll be sweet.

Anguyennn
 one year ago
Best ResponseYou've already chosen the best response.0do you have to put 6x^2y(2y3x+12) or just 2y3x+12?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Its has to be 6x^2y(2y3x+12) because remember you turned it into a number times brackets. You can check your answer by expanding, if you get the original expression then its right.

Anguyennn
 one year ago
Best ResponseYou've already chosen the best response.0wow thank you so much!!!!!!!!!!!!!!!!!!!!

Anguyennn
 one year ago
Best ResponseYou've already chosen the best response.0thanks for helping me so much it really helped me, now i understand the concept so much

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You are welcome :) As long as I teach you something I'll be happy. Good luck for any test you have.
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