At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

|dw:1442027403524:dw|

I count 6 edges connected to these vertices (circled)
|dw:1442027885574:dw|

or

Oh, ok. So I just erase one line ?

but then the outer vertices would only have 4 edges

Oh, that's right. Do I use the 2nd graph I have instead?

this seems to work though
|dw:1442028587295:dw|

|dw:1442028753021:dw|
the number in each circle represents the degree of each node

where is the curved not allowed to be plugged in?

what do you mean?

I was told this was impossible to do.

I'm still not sure what you mean? In my drawing? or the one you posted?

in general.

Maybe I heard wrong...

Hmm, can you check another problem for me?

alright

2) Find a cycle of length 20 in the following graph:

Since it's a cycle, I'm sure it's supposed to return to its starting point, no?

yeah you have to make a circuit and not repeat vertices

so they want you to find a circuit with 20 edges where you don't repeat vertices

your answer looks great

Thank you for checking my answers.

no problem