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gabbyalicorn
 one year ago
The width of a rectangle is 6 in. less than its length. The perimeter is 68 in.
What is the width of the rectangle?
in.
gabbyalicorn
 one year ago
The width of a rectangle is 6 in. less than its length. The perimeter is 68 in. What is the width of the rectangle? in.

This Question is Closed

pooja195
 one year ago
Best ResponseYou've already chosen the best response.1Uh i think the answer is in the question....if im right

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0divide it in two first

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1442028600183:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Omg I forgot the shapes have the "fill" option.... anyway.

gabbyalicorn
 one year ago
Best ResponseYou've already chosen the best response.1When you say divide two first, do you mean 68 ÷ 2 and 6÷ 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then subtract 6 from that

gabbyalicorn
 one year ago
Best ResponseYou've already chosen the best response.1okay, that is 34...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the length of the rectangle is given, but they say the `width` `is (equal to)` the `length  6 in`You can rewrite this as \(\sf w = L6\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So the Perimeter of a rectangle is represented as: \[\sf P = 2L +2W\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Since we're given the perimeter, and that is = 68 in. we can substitute that in to our formula. \[\sf 68 = 2L +2W\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0But we also know something else, \(\sf W=L6\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So we can substitute this in to the formula for the perimeter. \[\sf 68 = 2L+2(L6)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Are you following, @gabbyalicorn ?

gabbyalicorn
 one year ago
Best ResponseYou've already chosen the best response.1Um, somewhat... I don't really get it but i'm following the steps if that's what you mean. :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Which part are you confused with? Let's clarify that before moving on.

gabbyalicorn
 one year ago
Best ResponseYou've already chosen the best response.1is L the variable we are trying to find

gabbyalicorn
 one year ago
Best ResponseYou've already chosen the best response.1the number for...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0We are trying to find W (width). The problem indiscreetly gives us the equation for the width by saying that the width IS 6 LESS THAN the length. We can write an equation for that. \(\sf w = L6\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0But we can't automatically find the width, \(\sf w\) can we? We need to find the length, \(\sf L\) first.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That is where we use the equation for the perimeter of the rectangle. \(\sf P = 2L +2w\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do you see how this works?

gabbyalicorn
 one year ago
Best ResponseYou've already chosen the best response.1I think I'm getting it...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, so we have \[\sf 68 = 2L+2(L6)\] We need to first distribute (meaning multiply) 2 to each term inside the parenthesis. \[2 \cdot L =~?\]\[2\cdot (6) =~?\]

gabbyalicorn
 one year ago
Best ResponseYou've already chosen the best response.1dw:1442029733818:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\sf 68 = 2L +2L12\]We add +12 to both sides of the equation.

gabbyalicorn
 one year ago
Best ResponseYou've already chosen the best response.1why  12 I thought you said add

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0because we want to isolate the L's to one side of the equation, we need to eliminate the 12 from that side. In order to eliminate it we need to add +12 to it. \[\sf +1212 = 0\]So, \(\sf 68 + 12 =~?\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So now we have \[\sf 80 = 2L + 2L\]\[\sf 2L + 2L =~?\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\sf 80 = 4L\]Now we want to isolate the right side of the equation so we have JUST L. This is when we divide BOTH sides of the equation by 4. \[\sf \frac{80}{4}=~?\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ALRIGHT! So now we have figured out \(\sf L\). \[\sf L=20\]Now we can go back to our equation for width and plug in L. \[\sfW=L6\]So therefore what does W =?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Sorry, typo. \(\sf W=L6\)*

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Great! You worked it out yourself :)

gabbyalicorn
 one year ago
Best ResponseYou've already chosen the best response.1:D Thank you for helping me and not giving up on me! I reallu appreciate it. :)
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