anonymous
  • anonymous
Need help with 15 8th grade questions. Will medal and fan!
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
ill do my best to help you out :D
anonymous
  • anonymous
What is the solution to the equation?
anonymous
  • anonymous
-18+4+x=9-19 x=

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
so keep x on one side and move all the the other number to the other... you should end up with x=9-19+18-4, add them all up and there you have it :D
anonymous
  • anonymous
So, 4?
anonymous
  • anonymous
@Emeyluv99
anonymous
  • anonymous
4x-26-3x=16-20 x=
anonymous
  • anonymous
thats right
anonymous
  • anonymous
now for this second one, keep all the x's on one side and move everything else to the other
anonymous
  • anonymous
4-26-3=16-20? @emeyluv99
anonymous
  • anonymous
hang on, where are your x's you should be getting 4x-3x= 16-20+26
anonymous
  • anonymous
I don't know. I'm confused :x I don't understand this.
anonymous
  • anonymous
ok so you want to figure out the value of x. Yes?
anonymous
  • anonymous
Correctumundo.
anonymous
  • anonymous
so you have two numbers that are multiples of x, but, because you dont know what x is, you dont know what 4x or 3x is.
anonymous
  • anonymous
Yes.
anonymous
  • anonymous
so now, what we can do is put all the numbers that we know the value of (ie all the number that are not multiples of x) on one side, and keep the multiples of x on the other
anonymous
  • anonymous
this just helps us see what we do and dont know and makes it easier to solve.
anonymous
  • anonymous
go ahead and try it.
anonymous
  • anonymous
So, 4x-3x= 16-20+26
anonymous
  • anonymous
@Emeyluv99
anonymous
  • anonymous
good.
anonymous
  • anonymous
I just copied what you put earlier....xd
anonymous
  • anonymous
so now, what do you think 4x-3x is
anonymous
  • anonymous
(ahah cheeky)
anonymous
  • anonymous
I don't know!~ I am SO confused. No matter how it gets explained I don't understand.
anonymous
  • anonymous
ok lets try some experimenting then shall we?
anonymous
  • anonymous
We shall.
anonymous
  • anonymous
so lets pretend that x=5.
anonymous
  • anonymous
whats 3*5-4*5
anonymous
  • anonymous
5
anonymous
  • anonymous
NO!
anonymous
  • anonymous
-5
anonymous
  • anonymous
yes, youre correct
anonymous
  • anonymous
its - 5
anonymous
  • anonymous
15-20= -5
anonymous
  • anonymous
now try with x=20. whats 4*20-3*20
anonymous
  • anonymous
20
anonymous
  • anonymous
good
anonymous
  • anonymous
how about when x=30? whats 4*30-3*30?
anonymous
  • anonymous
120-90=30
anonymous
  • anonymous
I get this part.
anonymous
  • anonymous
ae you seeing a pattern here?
anonymous
  • anonymous
Yes.
anonymous
  • anonymous
so theres this rule in algebra. It goes somehting like this: ax+bx =(a+b)x
anonymous
  • anonymous
here a can be any number and b can be any number. id either of them are negative, that meass youre subtracting.
anonymous
  • anonymous
in your case, a is 4 and b is -3. see if you can work out what 4x-3x is with this rule
anonymous
  • anonymous
|dw:1442034277690:dw|
anonymous
  • anonymous
pardon! IF either of them are negative that MEANS you're subtracting
anonymous
  • anonymous
So, 16-9?
anonymous
  • anonymous
not quite. Using the rule you should get that 4x-3x= (4-3)x. which is just x.
anonymous
  • anonymous
..where is a and b?
anonymous
  • anonymous
like x a and b are variables.. so depending on the problem a and b can be any number
anonymous
  • anonymous
so in this problem, a= 4 and b=-3.
anonymous
  • anonymous
So, a and b in this problem was 4 and -3. So, it would actually be, 4x-3x= (4-3)x
anonymous
  • anonymous
exactly!
anonymous
  • anonymous
Just copied what you said earlier :x
anonymous
  • anonymous
haha, but do try to understand it.. it helps a LOT when you get into harder algebra.
anonymous
  • anonymous
How would it equal (4-3)x?
anonymous
  • anonymous
I GET IT!
anonymous
  • anonymous
We moved the x to one side leaving only 4-3!1!
anonymous
  • anonymous
YES! so now that means (4-3)x = x
anonymous
  • anonymous
So 1= x?
anonymous
  • anonymous
NO
anonymous
  • anonymous
thats getting a little far ahead. Bring back the equation we made earlier.
anonymous
  • anonymous
(4-3)x = x
anonymous
  • anonymous
4x-3x= 16-20+26
anonymous
  • anonymous
so what you have done is solved the left side of the equation. But, you cant ignore the right side!
anonymous
  • anonymous
We know that 4x-3x=x right?
anonymous
  • anonymous
Yes.
anonymous
  • anonymous
so what we do now, because x and 4x-3x have the SAME VALUE, we can say x= 16-20+26
anonymous
  • anonymous
So, x=22?
anonymous
  • anonymous
exactly!
anonymous
  • anonymous
I'm going to try ONE on my own. Stay here though, so you can tell me if I'm wrong.
anonymous
  • anonymous
sure thing!
anonymous
  • anonymous
The one I'm trying is -4x=5(x-2)=-16+10
anonymous
  • anonymous
go for it
anonymous
  • anonymous
Would the beginning be -4+5(-2)=-16+10xx?
anonymous
  • anonymous
hm.. not quite.
anonymous
  • anonymous
the thing is you have two equations here. take one at a time. start with -4x= 5(x-2) and then move on to 5(x-2) = -16+10
anonymous
  • anonymous
OK.
anonymous
  • anonymous
:( Confused now. T_T I REALLY want to get this! I just can't understand.
anonymous
  • anonymous
and also, remember the rule i showed you before? you'll have to use that here, but in reverse. Youll be doing (a+b)x= ax+bx
anonymous
  • anonymous
the hardest part in this is unravelling 5(x-2)
anonymous
  • anonymous
(-4+5)x=-4x+5x?
anonymous
  • anonymous
@Emeyluv99
anonymous
  • anonymous
exactly like that, but do that with the numbers you have in this equation. remember that a and b change depending on what your equation is.
anonymous
  • anonymous
Aren't a and b --5 and 5?
anonymous
  • anonymous
so if the rule is x(a+b), here, your x=5, a=x and b=-2. But this does not mean that your answer is x! because you ahve a whole other equation to solve!
anonymous
  • anonymous
(x+-2)5=-2*5+x*5
anonymous
  • anonymous
??
anonymous
  • anonymous
excellent!
anonymous
  • anonymous
so lets bring back the first of our two equation. -4x= 5(x-2)
anonymous
  • anonymous
you know what the 5(x-2) is now. so go ahead and replace that with what we found out with the rule
anonymous
  • anonymous
Wait what? Replace what?
anonymous
  • anonymous
so we found out that 5(x-2) = -2*5 + x*5 right?
anonymous
  • anonymous
Yes.
anonymous
  • anonymous
ok so, we know that both 5(x-2) and -2*5 +x*5 have the SAME VALUE
anonymous
  • anonymous
so whats stopping us from writing -4x= 5(x-2) as -4x= -2*5+x*5 ?
anonymous
  • anonymous
T_T I understand when you write it, but not how you got it! :(
anonymous
  • anonymous
lets make an analogy ok?
anonymous
  • anonymous
Yes ma'am.
anonymous
  • anonymous
oh please dont ma'am me, im only 15 ahah
anonymous
  • anonymous
I know, but you're my teacher (senpai), so you are ma'am.
anonymous
  • anonymous
hahah very well then!
anonymous
  • anonymous
but lets say we have we have a banana and two apples
anonymous
  • anonymous
Yes ma'am!
anonymous
  • anonymous
lets name this banana -4x
anonymous
  • anonymous
*laughs* OK...
anonymous
  • anonymous
now one of our apples is called 5(x-2) and we find out that the other one (called -2*5+x*5) has the exact same weight!
anonymous
  • anonymous
Yes ma'am! (making a sandwich, but keep explaining.)
anonymous
  • anonymous
Back.
anonymous
  • anonymous
so we put apple 5(x-2) and banana -4x on a set of scales and we see that they have the same weight
anonymous
  • anonymous
now because we know that apple 5(x-2) and apple -2*5+x*5 have the same weight, we replace apple 5(x-2) with apple -2*5+x*5
anonymous
  • anonymous
and what do you think we find between this new apple and the banana?
anonymous
  • anonymous
There's a weight difference?
anonymous
  • anonymous
ah remember that both apples have the same weight! so technically, switching them around makes no difference
anonymous
  • anonymous
OH! I get it!(nope)
anonymous
  • anonymous
say we take two different bags of flower same weight same everything
anonymous
  • anonymous
and we compare it to a brick of equal weight.
anonymous
  • anonymous
So everything is the same?
anonymous
  • anonymous
yes so if everything is the same,
anonymous
  • anonymous
the weight difference between bag 1 and the brick is 0, and the weight difference between bag 2 and the brick is?
anonymous
  • anonymous
0
anonymous
  • anonymous
exaclty so if both bags are the same, does it matter which one we compare it to?
anonymous
  • anonymous
Not at all ma'am.
anonymous
  • anonymous
similarly, 5(x-2) and -2*5+x*5 are have exactly the same "weight" (mathematically its value, but we'll say weight until you get the hang of it)
anonymous
  • anonymous
so does it matter which one we compare to -4x?
anonymous
  • anonymous
No ma'am.
anonymous
  • anonymous
so we choose to compare it to -2*5+x*5 because its easier to work with
anonymous
  • anonymous
which is why we had gotten -4x= -2*5+x*5
anonymous
  • anonymous
What is 'it' Ms. Luv?
anonymous
  • anonymous
'it" is -4x
anonymous
  • anonymous
OH!
anonymous
  • anonymous
im sensing a eureka moment!
anonymous
  • anonymous
so now we can take care of one of the two equations we made! -4x= -2*5+x*5 so get all the x's to one side and all the non x's to the other just like we did before
anonymous
  • anonymous
Eureka!! I still don't understand! (keep explaining)
anonymous
  • anonymous
remember it doesnt matter which one (5(x-2) or -2*5+x*5) we compare -4x to, we choose the second option because its easier for us to solve
anonymous
  • anonymous
Ugghh! MY BRAIN IS BUILT FOR ENGLISH, NOT MATH!!!
anonymous
  • anonymous
ahahah mines the otherway around. keep trying
anonymous
  • anonymous
i have to run to lunch give me 20 minutes please. keep trying ill be back soon!
anonymous
  • anonymous
Will do!
anonymous
  • anonymous
So, -30?@Mimi_x3 @j2lie
anonymous
  • anonymous
@Mimi_x3
madhu.mukherjee.946
  • madhu.mukherjee.946
whats your question btw?
anonymous
  • anonymous
-4x=5(x-2)=-16+10
anonymous
  • anonymous
x=?
madhu.mukherjee.946
  • madhu.mukherjee.946
|dw:1442038760084:dw|
anonymous
  • anonymous
so 32
anonymous
  • anonymous
@Emeyluv99
madhu.mukherjee.946
  • madhu.mukherjee.946
|dw:1442038811837:dw|
madhu.mukherjee.946
  • madhu.mukherjee.946
no |dw:1442038932820:dw|
madhu.mukherjee.946
  • madhu.mukherjee.946
|dw:1442038977386:dw|
madhu.mukherjee.946
  • madhu.mukherjee.946
@ShirouxGhoul do you understand
anonymous
  • anonymous
No...not yet. Help with a few more?
madhu.mukherjee.946
  • madhu.mukherjee.946
say
anonymous
  • anonymous
No...not yet. Help with a few more?
madhu.mukherjee.946
  • madhu.mukherjee.946
yes
anonymous
  • anonymous
-6.8+2.6+x=9.7 x=?
anonymous
  • anonymous
hey i'm back... if you still need help :D
anonymous
  • anonymous
I wish @Emeyluv99 was back! I ..EMEY!!!!!!
madhu.mukherjee.946
  • madhu.mukherjee.946
|dw:1442039191373:dw|
anonymous
  • anonymous
hello! your wish is granted ahah
anonymous
  • anonymous
so where are we now?
anonymous
  • anonymous
Emey, I don't do good with word problems, so please use a standard problem.
anonymous
  • anonymous
-6.8+2.6+x=9.7
anonymous
  • anonymous
got it.
madhu.mukherjee.946
  • madhu.mukherjee.946
|dw:1442039271587:dw|
madhu.mukherjee.946
  • madhu.mukherjee.946
okay bye then @Emeyluv99 will help you from now on
anonymous
  • anonymous
this is exactly like that first problem we did. move everything without x to one side and add em all up !
anonymous
  • anonymous
OK! Thank you so mcuh @madhu.mukherjee.946!! Tell me if you need help!
anonymous
  • anonymous
Hmm, we're polar opposites....
anonymous
  • anonymous
alrighty then @ShirouxGhoul, where are we
anonymous
  • anonymous
we do seem to be dont we.. ahah
anonymous
  • anonymous
-6.8+2.6+x=9.7
anonymous
  • anonymous
ah yes. so lets get everything that doesnt have x on one side, like we did before.
anonymous
  • anonymous
that would give us x=9.7+6.8-2.6
anonymous
  • anonymous
-4.2
anonymous
  • anonymous
13.9
anonymous
  • anonymous
yup
anonymous
  • anonymous
x=13.9?!
anonymous
  • anonymous
the trick to any algebra problem like the one's were doing right now is to always try and get x (or any other variable) alone on one side.
anonymous
  • anonymous
x=13.9?!
anonymous
  • anonymous
it is
anonymous
  • anonymous
The problem is done...?
anonymous
  • anonymous
yup
anonymous
  • anonymous
*mindblow*
anonymous
  • anonymous
hahaha see, x is antisocial and wants all the number to leave his side and go to the other side.
anonymous
  • anonymous
OMEGERD! It's SO complicated now!!
anonymous
  • anonymous
whats the next one? we'll get through this, hang in there!
anonymous
  • anonymous
1/3x+ 1/3 (2x-15) =3 1/2
anonymous
  • anonymous
x= blank blank over blank
anonymous
  • anonymous
ah fractions!
anonymous
  • anonymous
Mixed number I believe.
anonymous
  • anonymous
first tip to understand agebra with fractions, what does it mean when something is a fraction?
anonymous
  • anonymous
It's a part?
anonymous
  • anonymous
Of a whole?
anonymous
  • anonymous
yes so what are you doing to the whole to find that part. Adding? multiplying? Dividing or subracting?
anonymous
  • anonymous
Dividing, I believe.
anonymous
  • anonymous
correct.
anonymous
  • anonymous
are you familiar with the order of operations?
anonymous
  • anonymous
Yes!
anonymous
  • anonymous
Pemdas?
anonymous
  • anonymous
excellent! its going to make your life SO much easier here
anonymous
  • anonymous
I hope so!
anonymous
  • anonymous
oh hang on a second. this is different
anonymous
  • anonymous
scratch that sorry i read that wrong.
anonymous
  • anonymous
ok new board.
anonymous
  • anonymous
so when you have fractions in algebra, you reallly want to get rid of the denominators. How do you think you do that?
anonymous
  • anonymous
To get rid of the fractions, we pick a useful number and multiply both sides of the equation by that number. The number is useful if multiplying eliminates all fractions?
anonymous
  • anonymous
good!
anonymous
  • anonymous
Don't you just LOVE Google? ;x
anonymous
  • anonymous
i really do!
Jhannybean
  • Jhannybean
This is quite a long thread you have going :o
anonymous
  • anonymous
so when we have this in algebra, what we do is multiply EVERYTHING in the equation by BOTH denominators.
anonymous
  • anonymous
Well, since I Googled it, I get it now. (The denominator thing, not this thing)
anonymous
  • anonymous
so it will look somehthing like this.
anonymous
  • anonymous
@Jhannybean It's because I'm stupid, and it's impossible to explain things to me. :~
Jhannybean
  • Jhannybean
I mean... if that's what you want to believe....
anonymous
  • anonymous
@ShirouxGhoul You're not stupid! Dont say that! You'e brains just hardwired for English!
anonymous
  • anonymous
besides, you'll get the hang of algebra in time!
anonymous
  • anonymous
.....
Jhannybean
  • Jhannybean
Any other questions @ShirouxGhoul ? I can also give it a try! :)
anonymous
  • anonymous
$$\frac{1}{3x}+ \frac{1}{3 (2x-15)} =3 \frac{1}{2}$$ $$ (3(2x-15))(3x) \frac{1}{3x} + (3(2x-15))(3x) \frac{1}{3(2x-15)} = (3(2x-15))(3x) \frac{7}{2} $$
anonymous
  • anonymous
the second is what you get when you multiply the whole equation by both denominators on the right side!
Jhannybean
  • Jhannybean
whoah, thats too many steps all muddled into one.
anonymous
  • anonymous
true, let me break it down.
Jhannybean
  • Jhannybean
first and foremost, simplify everything. all fractions.
anonymous
  • anonymous
write 3 1/2 as an improper fraction first, it makes it easier to visualise everything
Jhannybean
  • Jhannybean
\[\sf 3\frac{1}{2} \implies \frac{(3\cdot 2)+1}{2} =~? \]
anonymous
  • anonymous
after you figure that out, choose one denominator, to get rid of. one at a time, we can get rid of all of them.
anonymous
  • anonymous
Internet went out for a min. Sorry!
anonymous
  • anonymous
no problem! so make the improper fraction and choose a denominator to eliminate first! we'll continue from there!
Jhannybean
  • Jhannybean
That's true, @Emeyluv99 , or you can look at \(\sf 3x\) , \(\sf 3(2x-15)\) and \(\sf 2\) and multiply both the numerator and denominator of each fraction with the multiplication between all 3 of these.
anonymous
  • anonymous
WHOA! Slow down! I am SO confused! You have to remember, i don't understand this all too well.
anonymous
  • anonymous
yes, lets take this one by one.
anonymous
  • anonymous
*I
Jhannybean
  • Jhannybean
Ok, ok, sorry!! I was referencing @Emeyluv99 :)
anonymous
  • anonymous
so @ShirouxGhoul already told me that the way to get rid of a denominator is to multiply the fraction.
Jhannybean
  • Jhannybean
Thats correct
anonymous
  • anonymous
so lets start one at a time. Well do 3x first
anonymous
  • anonymous
because we're dealing with an equation, we have to multiply EVERYTHING with 3x, not just that fraction. so that'll give us $$(3x) \frac{1}{3x}+(3x) \frac{1}{3(2x−15)}=(3x) \frac{7}{2}$$
anonymous
  • anonymous
in our first fraction, 3x cancels out with 3x, so it just becomes 1
anonymous
  • anonymous
@Jhannybean It's OK, I was just saying I was lost is all. :)
anonymous
  • anonymous
did you get that last bit?
anonymous
  • anonymous
Yes. So now we're left with 1 in place of x?
anonymous
  • anonymous
we're left with 1 in place of \[\frac{1}{3x}\]
anonymous
  • anonymous
$$1+(3x) \frac{1}{3(2x−15)}=(3x) \frac{7}{2}$$
anonymous
  • anonymous
do you see what i mean?
anonymous
  • anonymous
I think so.
anonymous
  • anonymous
@Emeyluv99???
anonymous
  • anonymous
yes im here, the internet 's being mean sorry
anonymous
  • anonymous
3(2x-15). We'll multiply everything in the equation by this to get: $$(3(2x-15)) 1 + (3(2x-15)) (3x) \frac{1}{3(2x-15)} = (3(2x-15)) (3x) \frac{7}{2}$$
Jhannybean
  • Jhannybean
Found the reason for the lag, 1. thread is WAY too long 2. it's taking a lot of time to load the latex. TRy opening a new question after you guys are done. Makes things easier.
anonymous
  • anonymous
@Jhannybean that makes a lt of sense.. thanks so much!

Looking for something else?

Not the answer you are looking for? Search for more explanations.