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anonymous
 one year ago
Need help with 15 8th grade questions. Will medal and fan!
anonymous
 one year ago
Need help with 15 8th grade questions. Will medal and fan!

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ill do my best to help you out :D

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What is the solution to the equation?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so keep x on one side and move all the the other number to the other... you should end up with x=919+184, add them all up and there you have it :D

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0now for this second one, keep all the x's on one side and move everything else to the other

anonymous
 one year ago
Best ResponseYou've already chosen the best response.04263=1620? @emeyluv99

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hang on, where are your x's you should be getting 4x3x= 1620+26

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I don't know. I'm confused :x I don't understand this.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok so you want to figure out the value of x. Yes?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so you have two numbers that are multiples of x, but, because you dont know what x is, you dont know what 4x or 3x is.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so now, what we can do is put all the numbers that we know the value of (ie all the number that are not multiples of x) on one side, and keep the multiples of x on the other

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0this just helps us see what we do and dont know and makes it easier to solve.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0go ahead and try it.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I just copied what you put earlier....xd

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so now, what do you think 4x3x is

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I don't know!~ I am SO confused. No matter how it gets explained I don't understand.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok lets try some experimenting then shall we?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so lets pretend that x=5.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0now try with x=20. whats 4*203*20

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how about when x=30? whats 4*303*30?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ae you seeing a pattern here?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so theres this rule in algebra. It goes somehting like this: ax+bx =(a+b)x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0here a can be any number and b can be any number. id either of them are negative, that meass youre subtracting.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0in your case, a is 4 and b is 3. see if you can work out what 4x3x is with this rule

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1442034277690:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0pardon! IF either of them are negative that MEANS you're subtracting

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0not quite. Using the rule you should get that 4x3x= (43)x. which is just x.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0like x a and b are variables.. so depending on the problem a and b can be any number

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so in this problem, a= 4 and b=3.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So, a and b in this problem was 4 and 3. So, it would actually be, 4x3x= (43)x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Just copied what you said earlier :x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0haha, but do try to understand it.. it helps a LOT when you get into harder algebra.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How would it equal (43)x?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0We moved the x to one side leaving only 43!1!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0YES! so now that means (43)x = x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thats getting a little far ahead. Bring back the equation we made earlier.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so what you have done is solved the left side of the equation. But, you cant ignore the right side!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0We know that 4x3x=x right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so what we do now, because x and 4x3x have the SAME VALUE, we can say x= 1620+26

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm going to try ONE on my own. Stay here though, so you can tell me if I'm wrong.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The one I'm trying is 4x=5(x2)=16+10

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Would the beginning be 4+5(2)=16+10xx?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the thing is you have two equations here. take one at a time. start with 4x= 5(x2) and then move on to 5(x2) = 16+10

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0:( Confused now. T_T I REALLY want to get this! I just can't understand.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and also, remember the rule i showed you before? you'll have to use that here, but in reverse. Youll be doing (a+b)x= ax+bx

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the hardest part in this is unravelling 5(x2)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0exactly like that, but do that with the numbers you have in this equation. remember that a and b change depending on what your equation is.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Aren't a and b 5 and 5?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so if the rule is x(a+b), here, your x=5, a=x and b=2. But this does not mean that your answer is x! because you ahve a whole other equation to solve!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so lets bring back the first of our two equation. 4x= 5(x2)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you know what the 5(x2) is now. so go ahead and replace that with what we found out with the rule

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Wait what? Replace what?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so we found out that 5(x2) = 2*5 + x*5 right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok so, we know that both 5(x2) and 2*5 +x*5 have the SAME VALUE

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so whats stopping us from writing 4x= 5(x2) as 4x= 2*5+x*5 ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0T_T I understand when you write it, but not how you got it! :(

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lets make an analogy ok?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh please dont ma'am me, im only 15 ahah

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I know, but you're my teacher (senpai), so you are ma'am.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hahah very well then!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but lets say we have we have a banana and two apples

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lets name this banana 4x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0now one of our apples is called 5(x2) and we find out that the other one (called 2*5+x*5) has the exact same weight!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes ma'am! (making a sandwich, but keep explaining.)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so we put apple 5(x2) and banana 4x on a set of scales and we see that they have the same weight

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0now because we know that apple 5(x2) and apple 2*5+x*5 have the same weight, we replace apple 5(x2) with apple 2*5+x*5

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and what do you think we find between this new apple and the banana?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0There's a weight difference?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ah remember that both apples have the same weight! so technically, switching them around makes no difference

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0say we take two different bags of flower same weight same everything

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and we compare it to a brick of equal weight.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So everything is the same?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes so if everything is the same,

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the weight difference between bag 1 and the brick is 0, and the weight difference between bag 2 and the brick is?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0exaclty so if both bags are the same, does it matter which one we compare it to?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0similarly, 5(x2) and 2*5+x*5 are have exactly the same "weight" (mathematically its value, but we'll say weight until you get the hang of it)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so does it matter which one we compare to 4x?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so we choose to compare it to 2*5+x*5 because its easier to work with

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0which is why we had gotten 4x= 2*5+x*5

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What is 'it' Ms. Luv?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im sensing a eureka moment!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so now we can take care of one of the two equations we made! 4x= 2*5+x*5 so get all the x's to one side and all the non x's to the other just like we did before

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Eureka!! I still don't understand! (keep explaining)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0remember it doesnt matter which one (5(x2) or 2*5+x*5) we compare 4x to, we choose the second option because its easier for us to solve

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ugghh! MY BRAIN IS BUILT FOR ENGLISH, NOT MATH!!!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ahahah mines the otherway around. keep trying

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i have to run to lunch give me 20 minutes please. keep trying ill be back soon!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So, 30?@Mimi_x3 @j2lie

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0whats your question btw?

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0dw:1442038760084:dw

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0dw:1442038811837:dw

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0no dw:1442038932820:dw

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0dw:1442038977386:dw

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0@ShirouxGhoul do you understand

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No...not yet. Help with a few more?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No...not yet. Help with a few more?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hey i'm back... if you still need help :D

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I wish @Emeyluv99 was back! I ..EMEY!!!!!!

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0dw:1442039191373:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hello! your wish is granted ahah

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so where are we now?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Emey, I don't do good with word problems, so please use a standard problem.

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0dw:1442039271587:dw

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0okay bye then @Emeyluv99 will help you from now on

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0this is exactly like that first problem we did. move everything without x to one side and add em all up !

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0OK! Thank you so mcuh @madhu.mukherjee.946!! Tell me if you need help!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Hmm, we're polar opposites....

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0alrighty then @ShirouxGhoul, where are we

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0we do seem to be dont we.. ahah

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ah yes. so lets get everything that doesnt have x on one side, like we did before.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that would give us x=9.7+6.82.6

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the trick to any algebra problem like the one's were doing right now is to always try and get x (or any other variable) alone on one side.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The problem is done...?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hahaha see, x is antisocial and wants all the number to leave his side and go to the other side.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0OMEGERD! It's SO complicated now!!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0whats the next one? we'll get through this, hang in there!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.01/3x+ 1/3 (2x15) =3 1/2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0x= blank blank over blank

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Mixed number I believe.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0first tip to understand agebra with fractions, what does it mean when something is a fraction?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes so what are you doing to the whole to find that part. Adding? multiplying? Dividing or subracting?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Dividing, I believe.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0are you familiar with the order of operations?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0excellent! its going to make your life SO much easier here

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh hang on a second. this is different

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0scratch that sorry i read that wrong.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so when you have fractions in algebra, you reallly want to get rid of the denominators. How do you think you do that?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0To get rid of the fractions, we pick a useful number and multiply both sides of the equation by that number. The number is useful if multiplying eliminates all fractions?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Don't you just LOVE Google? ;x

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0This is quite a long thread you have going :o

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so when we have this in algebra, what we do is multiply EVERYTHING in the equation by BOTH denominators.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well, since I Googled it, I get it now. (The denominator thing, not this thing)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so it will look somehthing like this.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Jhannybean It's because I'm stupid, and it's impossible to explain things to me. :~

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0I mean... if that's what you want to believe....

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@ShirouxGhoul You're not stupid! Dont say that! You'e brains just hardwired for English!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0besides, you'll get the hang of algebra in time!

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0Any other questions @ShirouxGhoul ? I can also give it a try! :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0$$\frac{1}{3x}+ \frac{1}{3 (2x15)} =3 \frac{1}{2}$$ $$ (3(2x15))(3x) \frac{1}{3x} + (3(2x15))(3x) \frac{1}{3(2x15)} = (3(2x15))(3x) \frac{7}{2} $$

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the second is what you get when you multiply the whole equation by both denominators on the right side!

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0whoah, thats too many steps all muddled into one.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0true, let me break it down.

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0first and foremost, simplify everything. all fractions.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0write 3 1/2 as an improper fraction first, it makes it easier to visualise everything

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0\[\sf 3\frac{1}{2} \implies \frac{(3\cdot 2)+1}{2} =~? \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0after you figure that out, choose one denominator, to get rid of. one at a time, we can get rid of all of them.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Internet went out for a min. Sorry!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no problem! so make the improper fraction and choose a denominator to eliminate first! we'll continue from there!

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0That's true, @Emeyluv99 , or you can look at \(\sf 3x\) , \(\sf 3(2x15)\) and \(\sf 2\) and multiply both the numerator and denominator of each fraction with the multiplication between all 3 of these.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0WHOA! Slow down! I am SO confused! You have to remember, i don't understand this all too well.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes, lets take this one by one.

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0Ok, ok, sorry!! I was referencing @Emeyluv99 :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so @ShirouxGhoul already told me that the way to get rid of a denominator is to multiply the fraction.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so lets start one at a time. Well do 3x first

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0because we're dealing with an equation, we have to multiply EVERYTHING with 3x, not just that fraction. so that'll give us $$(3x) \frac{1}{3x}+(3x) \frac{1}{3(2x−15)}=(3x) \frac{7}{2}$$

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0in our first fraction, 3x cancels out with 3x, so it just becomes 1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Jhannybean It's OK, I was just saying I was lost is all. :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0did you get that last bit?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes. So now we're left with 1 in place of x?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0we're left with 1 in place of \[\frac{1}{3x}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0$$1+(3x) \frac{1}{3(2x−15)}=(3x) \frac{7}{2}$$

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do you see what i mean?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes im here, the internet 's being mean sorry

anonymous
 one year ago
Best ResponseYou've already chosen the best response.03(2x15). We'll multiply everything in the equation by this to get: $$(3(2x15)) 1 + (3(2x15)) (3x) \frac{1}{3(2x15)} = (3(2x15)) (3x) \frac{7}{2}$$

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0Found the reason for the lag, 1. thread is WAY too long 2. it's taking a lot of time to load the latex. TRy opening a new question after you guys are done. Makes things easier.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Jhannybean that makes a lt of sense.. thanks so much!
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