anonymous
  • anonymous
Help! Will fan and give medal
Algebra
chestercat
  • chestercat
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MTALHAHASSAN2
  • MTALHAHASSAN2
Ok I will
anonymous
  • anonymous
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ganeshie8
  • ganeshie8
Look at the graph. What part of it is shaded blue ?

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anonymous
  • anonymous
-2
anonymous
  • anonymous
Its something like \[-2 \le x\]
anonymous
  • anonymous
right?
ganeshie8
  • ganeshie8
also everything before -2 is shaded blue so the inequality that represents the shaded region is \(x\le -2\)
anonymous
  • anonymous
ah okay so the other way around. Got it. Just wanted to correct myself
ganeshie8
  • ganeshie8
good \(x\color{Red}{\le} -2\) is read as \(x ~\color{red}{\text{less than or equal to}} -2 \)
anonymous
  • anonymous
Right right yes Thanks! @ganeshie8 Hey do you mind checking this if im right?
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ganeshie8
  • ganeshie8
Very close! Inequality for left shaded region is correct, but the other part isn't
ganeshie8
  • ganeshie8
Oh no wait, left part is starting at \(-2\), yes ?
anonymous
  • anonymous
Right right yes Thanks! @ganeshie8 Hey do you mind checking this if im right?
ganeshie8
  • ganeshie8
so whatss ur updated answer?
anonymous
  • anonymous
Uhh im going with \[x \ge 3\]
ganeshie8
  • ganeshie8
That is correct for the right side shaded part what about the left side shaded part ?
anonymous
  • anonymous
would the x be on the opposite side? so \[2
ganeshie8
  • ganeshie8
Mope, \(x\) represents any number in the shaded region. It should be \(x\lt -2\) OR \(x\ge 3\)
anonymous
  • anonymous
ahh yes sorry I forgot the -2. alright now I get it! Thanks so much!
ganeshie8
  • ganeshie8
also you need to be careful about when to use OR, when to use AND
anonymous
  • anonymous
so I shouldn't put, and ?
anonymous
  • anonymous
I think when its split you use and. I dont know about or
ganeshie8
  • ganeshie8
http://freemathresource.com/images/stories/Algebra/Inequalities/Graph_Comp_Inequalities/Graph_Comp_Ineq_vis_2.png
anonymous
  • anonymous
You are a life saver
anonymous
  • anonymous
Thank you again, this will help
ganeshie8
  • ganeshie8
np:)

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