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anonymous
 one year ago
Help!
anonymous
 one year ago
Help!

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.01/3x+ 1/3 (2x15) =3 1/2

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0That's much better.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0$$(3(2x15) 1 + (3(2x15)) (3x) \frac{1}{(3(2x15))} = (3(2x15)) (3x) \frac{7}{2}$$

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0At the second denominator.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes, so when we multiply by the second denominator, we get ^^ that mess up there

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so lets simplify the second equation when the (3(2x15)) cancels itself out

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0$$(3(2x15)) 1 + (3x) 1 = (3(2x15)) (3x) \frac{7}{2}$$

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0Original question: \[\sf \frac{1}{3x}+\frac{1}{3(2x15)}=\frac{7}{2}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it'll be worth it in the end! lets finish off the last denominator! 2!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0$$2(3(2x−15))1+2(3x)1=2(3(2x−15))(3x) \frac{7}{2}$$

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that pic is awesome by the way

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Mys is loves drawing like you and ok.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so simplify the problem out: 6(2x15) + 6x = 9x(3x15)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Wait, I thought x's were out?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no not yet, because we had to multiply by the denominators and the denominators had x's in them

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0its our job now to get rid of them.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and its quite easy too, no calculator required! watch!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.06(2x15) + 6x = 9x(2x15) 6(2x15)  9x(2x15) = 6x < I just switched the places of 9x(2x15) and 6x, because now i can use the ax+bx = (a+b) x rule.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can we eliminate x's now?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so that would give you (2x15)(69x) = 6x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0to basically, what we have now on the left side is a factored quadratic.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry, SO, we have a factored quadratic on the left. which equates to 6x.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what you have to do now is expand the quadratic on the left which will give you $$147x18x^290=6x$$

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then you get rid of 6x by adding 6x to both sides: $$147x12x^290=0$$

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then you factor it again. ...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Session expired. :( It's OK though, you have some physics right? :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ugh hang on, we mustve done somehting wrong... im getting radicals

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ill get back to you later, i have some homework to do... is that ok?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It's fine. I could try to help if you want.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im writing a lab up so its fine... thanks tho!
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