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1/3x+ 1/3 (2x-15) =3 1/2
That's much better.

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now where were we.
$$(3(2x-15) 1 + (3(2x-15)) (3x) \frac{1}{(3(2x-15))} = (3(2x-15)) (3x) \frac{7}{2}$$
At the second denominator.
yes, so when we multiply by the second denominator, we get ^^ that mess up there
so lets simplify the second equation when the (3(2x-15)) cancels itself out
$$(3(2x-15)) 1 + (3x) 1 = (3(2x-15)) (3x) \frac{7}{2}$$
Original question: \[\sf \frac{1}{3x}+\frac{1}{3(2x-15)}=\frac{7}{2}\]
oh my, it does
it'll be worth it in the end! lets finish off the last denominator! 2!
1 Attachment
$$2(3(2x−15))1+2(3x)1=2(3(2x−15))(3x) \frac{7}{2}$$
Nice anime pic x'3
that pic is awesome by the way
Mys is loves drawing like you and ok.
my sis*
so simplify the problem out: 6(2x-15) + 6x = 9x(3x-15)
Wait, I thought x's were out?
no not yet, because we had to multiply by the denominators and the denominators had x's in them
its our job now to get rid of them.
and its quite easy too, no calculator required! watch!
6(2x-15) + 6x = 9x(2x-15) 6(2x-15) - 9x(2x-15) = -6x <- I just switched the places of 9x(2x-15) and 6x, because now i can use the ax+bx = (a+b) x rule.
Following so far.
Can we eliminate x's now?
so that would give you (2x-15)(6-9x) = -6x
to basically, what we have now on the left side is a factored quadratic.
To baically? What?
sorry, SO, we have a factored quadratic on the left. which equates to -6x.
K.
what you have to do now is expand the quadratic on the left which will give you $$147x-18x^2-90=-6x$$
then you get rid of -6x by adding 6x to both sides: $$147x-12x^2-90=0$$
then you factor it again. ...
Session expired. :( It's OK though, you have some physics right? :)
ugh hang on, we mustve done somehting wrong... im getting radicals
ill get back to you later, i have some homework to do... is that ok?
It's fine. I could try to help if you want.
im writing a lab up so its fine... thanks tho!

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