alphabeta
  • alphabeta
How to find the instantaneous acceleration by looking at this graph (file attached) at time 0.50s?
Physics
  • Stacey Warren - Expert brainly.com
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jamiebookeater
  • jamiebookeater
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alphabeta
  • alphabeta
1 Attachment
Abhisar
  • Abhisar
|dw:1442065747164:dw| Hey alphabeta! Acceleration is the rate of change in velocity or in other words, \(\sf acceleration = \Large \frac{dv}{dt}\)= Slope of Velocity-time graph. So, let's suppose we want to calculate the acceleration of the body at t=1 sec, then slope will roughly be equal to 6 over 1 = \(\sf \Large \frac{6}{1}\)
alphabeta
  • alphabeta
Thanks @Abhisar ! That really helped a lot! :-)

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Abhisar
  • Abhisar
You're welcome c:
alphabeta
  • alphabeta
At least I thought I understood? For some reason, I don't get the right answer! I'm doing it like this: (4.2ms^-1)/(0.50s) = 8.4 ms^-2, but the markscheme says 4.5ms^-2... But when thinking about it, isn't this the average acceleration rather than the instantaneous?
alphabeta
  • alphabeta
@Abhisar
Abhisar
  • Abhisar
What do you want to figure out, instantaneous acceleration or average acceleration?
alphabeta
  • alphabeta
Instantaneous (as written in my first post) :-)
Abhisar
  • Abhisar
Well, in that case it should be 8.4 m/s^2. That's what I believe but let's call @IrishBoy123 to counter check it.
IrishBoy123
  • IrishBoy123
|dw:1442072505379:dw|you need the slope of the tangent line at t = 0.5 i think @Abhisar 's line is parallel and gives you a very good approximation so your denominator should be 1 in your calculation but it's just an approximation, isn't it :p
IrishBoy123
  • IrishBoy123
that's for **instantaneous acceleration** at t = 0.5, to be clear. the slope at that instant
Abhisar
  • Abhisar
Yeah, basically it needs to be a tangent drawn through the curve as you have drawn.
Abhisar
  • Abhisar
Thanks c:
Astrophysics
  • Astrophysics
|dw:1442092345797:dw| I am approximating as we don't have a computer to be exact, and as you were still confused maybe this will clear things up a bit @alphabeta this is for instantaneous acceleration, keeping it simple \[a = \frac{ \Delta v }{ \Delta t }\] notice we take the slope of the line here at that instant.
alphabeta
  • alphabeta
Ahh, now I see! Thanks soo much! :-D
Astrophysics
  • Astrophysics
Yw :)

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