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anonymous
 one year ago
I'm having a difficult time finding inverse functions for polynomials. I know I'm close.
Find the inverse function for:
h(t)=5t^2+10t+2
Rewrite:
h=5t^2+10t+2
Swap variables:
t=5h^2+10h+2
Solve for h:
5h^210h=2t
5(h^22h)=2t
h^22h=(2t)/5
h(h2)=(2t)/5
And this is where I'm stuck.
anonymous
 one year ago
I'm having a difficult time finding inverse functions for polynomials. I know I'm close. Find the inverse function for: h(t)=5t^2+10t+2 Rewrite: h=5t^2+10t+2 Swap variables: t=5h^2+10h+2 Solve for h: 5h^210h=2t 5(h^22h)=2t h^22h=(2t)/5 h(h2)=(2t)/5 And this is where I'm stuck.

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radar
 one year ago
Best ResponseYou've already chosen the best response.1It looks like you were going the right direction. Lets go to the next to last line of your post.:\[h ^{2}2h =(2t)/5\] Now I would use the "completing the square" method to solve this;\[h ^{2}2h +1 = (25)/5 + 5/5 = (7t)/5\] Notice that I added a "1" to the left hand side to make that a perfect square, but I had to also add a 1 or 5/5 to the right hand side to maintain the equality. I further simplified the right hand side. You now must take the square root of both sides. This gives you:\[h1 =\sqrt{(7t)/5}\] I am sure you can now take this from here and solve.

radar
 one year ago
Best ResponseYou've already chosen the best response.1You're welcome, good luck with your studies.
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