## anonymous one year ago SOLVE FOR T: 6P=Pe^(1.4t)

1. Nnesha

first we need to get rid of p at right side

2. Nnesha

how would you cancel out p from right side ?

3. Nnesha

do you know ? yes or no ?

4. anonymous

No, I don't know

5. anonymous

@Nnesha

6. Nnesha

it's p times e^P(1.4t) so to cancel out p from right side do opposite of multiplication

7. anonymous

Divide by P on both sides to cancel P?

8. Nnesha

yes right

9. Nnesha

$\huge\rm \frac{ 6p }{ p}=\frac{ pe^{(1.4t)} }{ p }$ what do you get ?

10. anonymous

6=e^(1.4t)

11. Nnesha

yes right not take natural log both sides to cancel out the e $\huge\rm \cancel{ln e}^a = a$bec ln and e cancel each other out

12. anonymous

t= 1.2798 ?

13. Nnesha

hm no how did you get that

14. Nnesha

oh wait

15. anonymous

ln of 6 divided by 1.4? is that wrong?

16. Nnesha

yes that's right

17. anonymous

Yay!!!

18. Nnesha

Yahoo!!! good job!

19. anonymous

thanks so much!

20. Nnesha

yw :=)