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anonymous

  • one year ago

SOLVE FOR T: 6P=Pe^(1.4t)

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  1. Nnesha
    • one year ago
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    first we need to get rid of p at right side

  2. Nnesha
    • one year ago
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    how would you cancel out p from right side ?

  3. Nnesha
    • one year ago
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    do you know ? yes or no ?

  4. anonymous
    • one year ago
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    No, I don't know

  5. anonymous
    • one year ago
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    @Nnesha

  6. Nnesha
    • one year ago
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    it's p `times` e^P(1.4t) so to cancel out p from right side do opposite of `multiplication `

  7. anonymous
    • one year ago
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    Divide by P on both sides to cancel P?

  8. Nnesha
    • one year ago
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    yes right

  9. Nnesha
    • one year ago
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    \[\huge\rm \frac{ 6p }{ p}=\frac{ pe^{(1.4t)} }{ p }\] what do you get ?

  10. anonymous
    • one year ago
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    6=e^(1.4t)

  11. Nnesha
    • one year ago
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    yes right not take natural log both sides to cancel out the e \[\huge\rm \cancel{ln e}^a = a\]bec ln and e cancel each other out

  12. anonymous
    • one year ago
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    t= 1.2798 ?

  13. Nnesha
    • one year ago
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    hm no how did you get that

  14. Nnesha
    • one year ago
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    oh wait

  15. anonymous
    • one year ago
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    ln of 6 divided by 1.4? is that wrong?

  16. Nnesha
    • one year ago
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    yes that's right

  17. anonymous
    • one year ago
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    Yay!!!

  18. Nnesha
    • one year ago
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    Yahoo!!! good job!

  19. anonymous
    • one year ago
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    thanks so much!

  20. Nnesha
    • one year ago
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    yw :=)

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