SOLVE FOR T: 6P=Pe^(1.4t)

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SOLVE FOR T: 6P=Pe^(1.4t)

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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first we need to get rid of p at right side
how would you cancel out p from right side ?
do you know ? yes or no ?

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Other answers:

No, I don't know
it's p `times` e^P(1.4t) so to cancel out p from right side do opposite of `multiplication `
Divide by P on both sides to cancel P?
yes right
\[\huge\rm \frac{ 6p }{ p}=\frac{ pe^{(1.4t)} }{ p }\] what do you get ?
6=e^(1.4t)
yes right not take natural log both sides to cancel out the e \[\huge\rm \cancel{ln e}^a = a\]bec ln and e cancel each other out
t= 1.2798 ?
hm no how did you get that
oh wait
ln of 6 divided by 1.4? is that wrong?
yes that's right
Yay!!!
Yahoo!!! good job!
thanks so much!
yw :=)

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