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shelby1290
 one year ago
Use the suggested method to sketch the graph of each linear relationship.
a) y= 4x+3 (slope, yintercept method)
b) 2xy=4 (x,yintercept method)
c) 3x=6y3 (table of values)
shelby1290
 one year ago
Use the suggested method to sketch the graph of each linear relationship. a) y= 4x+3 (slope, yintercept method) b) 2xy=4 (x,yintercept method) c) 3x=6y3 (table of values)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0a.) y = 4x + 3  slope, y int method.. In y = mx + b form, the slope is in the m position and the y intercept is in the b position. So...the slope is 4 (same as 4/1) and the y int is 3, or (0,3). First we plot out y int points (0,3).....and since our slope is 4/1, we come down 4 units (because of the negative), and go right 1 unit, then down 4 units, the to the right 1.. If you want to make sure you are doing it right, find the x int by subbing in 0 for y. y = 4x + 3 0 = 4x + 3 4x = 3 x = 3/4....so the x int is (3/4,0) And following the slope, coming down from (0,3).....coming down 4 and to the right 1, you should cross the x axis at (3/4,0) Looks like this .. http://www.metacalculator.com/online/?panel102graph&databoundsxMin=10&databoundsxMax=10&databoundsyMin=7.28&databoundsyMax=7.28&dataequations0=%22y%20%3D%204*x%20%2B%203%22&datarand=undefined&datahideGrid=false any questions about this one ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0b.) 2x  y = 4 ....x and y intercept method To find x intercept, sub in 0 for y 2x  0 = 4 2x = 4 x = 2.....so the x intercept is (2,0) To find the y intercept, sub in 0 for x 2(0)  y = 4 y = 4 y = 4 ...so the y intercept is (0,4) so now you plot your points (2,0) and (0,4)......connect them with a solid line Looks like this... http://www.metacalculator.com/online/?panel102graph&databoundsxMin=10&databoundsxMax=10&databoundsyMin=7.28&databoundsyMax=7.28&dataequations0=%222*x%20%20y%20%3D%204%22&datarand=undefined&datahideGrid=false

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0c.) 3x  6y = 3.....now we will sub in numbers for x to find y Lets let x = 0 3(0)  6y = 3 6y = 3 y = 1/2 Lets let x be 1 3(1)  6y = 3 3  6y = 3 6y = 3  3 6y = 0 y = 0 Lets let x be 2 3(2)  6y = 3 6  6y = 3 6y = 3  6 6y = 3 y = 1/2 one more...let x be 3 3(3)  6y = 3 9  6y = 3 6y = 3  9 6y = 6 y = 1 so...out table now has 4 sets of points... x  y  0 1/2 1 0 2 1/2 3 1 Now it is just a matter of plotting your points (0,1/2) , (1,0), (2,1/2) , (3,1) Looks like this... http://www.metacalculator.com/online/?panel102graph&databoundsxMin=10&databoundsxMax=10&databoundsyMin=7.28&databoundsyMax=7.28&dataequations0=%223*x%20%206*y%20%3D%203%22&datarand=undefined&datahideGrid=false

shelby1290
 one year ago
Best ResponseYou've already chosen the best response.0@texaschic101 wow thank you so much
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