Which equation represents the reduction half-reaction for this redox equation? Mg + CuSO4 MgSO4 + Cu A. Cu Cu B. Cu + 2e- Cu C. Cu Cu + 2e- D. Cu + 3e- Cu

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Which equation represents the reduction half-reaction for this redox equation? Mg + CuSO4 MgSO4 + Cu A. Cu Cu B. Cu + 2e- Cu C. Cu Cu + 2e- D. Cu + 3e- Cu

Chemistry
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Ok, what do you think it should be? Any Idea?
honestly, not a clue... This is my first time taking chemistry.. & i am LOST.

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Fine, do you know what defines a reduction reaction ?
Yes/No?
no.. ? but i can google it. lol
Ok, reduction reaction is when any species gains electron. The reaction which you have been given can be written as follows:- \(\sf Mg + Cu^{+2}+SO4^{-2} \rightarrow Mg^{+2}+SO4^{-2} + Cu\)
Now tell which species on the reactant side has gained electron?
Which one has =+ve charge on the left hand side but is neutral on right hand side?
cu?
Yes, so we can say that the reduction half is :- \(\sf Cu^{2+} +2e^- \rightarrow Cu\) Notice since it had 2+ charge before and neutral after that's why it must have gained 2 electrons.
so the answer is B?
Isn't that obvious ? c:
that's what i chose. thanks!!
You're welcome c:

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