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anonymous

  • one year ago

Which equation represents the reduction half-reaction for this redox equation? Mg + CuSO4 MgSO4 + Cu A. Cu Cu B. Cu + 2e- Cu C. Cu Cu + 2e- D. Cu + 3e- Cu

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  1. anonymous
    • one year ago
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    @Abhisar

  2. Abhisar
    • one year ago
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    Ok, what do you think it should be? Any Idea?

  3. anonymous
    • one year ago
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    honestly, not a clue... This is my first time taking chemistry.. & i am LOST.

  4. Abhisar
    • one year ago
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    Fine, do you know what defines a reduction reaction ?

  5. Abhisar
    • one year ago
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    Yes/No?

  6. anonymous
    • one year ago
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    no.. ? but i can google it. lol

  7. Abhisar
    • one year ago
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    Ok, reduction reaction is when any species gains electron. The reaction which you have been given can be written as follows:- \(\sf Mg + Cu^{+2}+SO4^{-2} \rightarrow Mg^{+2}+SO4^{-2} + Cu\)

  8. Abhisar
    • one year ago
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    Now tell which species on the reactant side has gained electron?

  9. Abhisar
    • one year ago
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    Which one has =+ve charge on the left hand side but is neutral on right hand side?

  10. anonymous
    • one year ago
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    cu?

  11. Abhisar
    • one year ago
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    Yes, so we can say that the reduction half is :- \(\sf Cu^{2+} +2e^- \rightarrow Cu\) Notice since it had 2+ charge before and neutral after that's why it must have gained 2 electrons.

  12. anonymous
    • one year ago
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    so the answer is B?

  13. Abhisar
    • one year ago
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    Isn't that obvious ? c:

  14. anonymous
    • one year ago
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    that's what i chose. thanks!!

  15. Abhisar
    • one year ago
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    You're welcome c:

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